std::ranges::shift_left, std::ranges::shift_right
Defined in header <algorithm> | ||
Call signature | ||
template<std::permutable I, std::sentinel_for<I> S > constexprranges::subrange<I> | (1) | (since C++23) |
template<ranges::forward_range R > requires std::permutable<ranges::iterator_t<R>> | (2) | (since C++23) |
template<std::permutable I, std::sentinel_for<I> S > constexprranges::subrange<I> | (3) | (since C++23) |
template<ranges::forward_range R > requires std::permutable<ranges::iterator_t<R>> | (4) | (since C++23) |
Shifts the elements in the range [
first,
last)
or r by n
positions. The behavior is undefined if [
first,
last)
is not a valid range.
- If n ==0|| n >= last - first, there are no effects.
- If n <0, the behavior is undefined.
- Otherwise, for every integer
i
in[
0,
last - first - n)
, moves the element originally at position first + n + i to position first + i. The moves are performed in increasing order ofi
starting from 0.
- If n ==0|| n >= last - first, there are no effects.
- If n <0, the behavior is undefined.
- Otherwise, for every integer
i
in[
0,
last - first - n)
, moves the element originally at position first + i to position first + n + i. IfI
modelsbidirectional_iterator
, then the moves are performed in decreasing order ofi
starting from last - first - n -1.
Elements that are in the original range but not the new range are left in a valid but unspecified state.
The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:
- Explicit template argument lists cannot be specified when calling any of them.
- None of them are visible to argument-dependent lookup.
- When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.
Contents |
[edit]Parameters
first, last | - | the iterator-sentinel pair defining the range of elements to shift |
r | - | the range of elements to shift |
n | - | the number of positions to shift |
[edit]Return value
NEW_LAST
is the end of the resulting range and equivalent to: - first +(last - first - n), if
n
is less than last - first; - first otherwise.
NEW_FIRST
is the beginning of the resulting range and equivalent to: - first + n, if
n
is less than last - first; - last otherwise.
[edit]Complexity
[edit]Notes
ranges::shift_left
/ ranges::shift_right
has better efficiency on common implementations if I
models bidirectional_iterator
or (better) random_access_iterator
.
Implementations (e.g. MSVC STL) may enable vectorization when the iterator type models contiguous_iterator
and swapping its value type calls neither non-trivial special member function nor ADL-found swap
.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_shift | 202202L | (C++23) | std::ranges::shift_left and std::ranges::shift_right |
[edit]Example
#include <algorithm>#include <iostream>#include <string>#include <type_traits>#include <vector> struct S {int value{0};bool specified_state{true}; S(int v =0): value{v}{} S(S const& rhs)=default; S(S&& rhs){*this = std::move(rhs);} S& operator=(S const& rhs)=default; S& operator=(S&& rhs){if(this !=&rhs){ value = rhs.value; specified_state = rhs.specified_state; rhs.specified_state=false;}return*this;}}; template<typename T>std::ostream& operator<<(std::ostream& os, std::vector<T>const& v){for(constauto& s : v){ifconstexpr(std::is_same_v<T, S>) s.specified_state? os << s.value<<' ': os <<". ";elseifconstexpr(std::is_same_v<T, std::string>) os <<(s.empty()?".": s)<<' ';else os << s <<' ';}return os;} int main(){std::cout<<std::left; std::vector<S> a{1, 2, 3, 4, 5, 6, 7};std::vector<int> b{1, 2, 3, 4, 5, 6, 7};std::vector<std::string> c{"α", "β", "γ", "δ", "ε", "ζ", "η"}; std::cout<<"vector<S> \tvector<int> \tvector<string>\n";std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::ranges::shift_left(a, 3); std::ranges::shift_left(b, 3); std::ranges::shift_left(c, 3);std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::ranges::shift_right(a, 2); std::ranges::shift_right(b, 2); std::ranges::shift_right(c, 2);std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::ranges::shift_left(a, 8);// has no effect: n >= last - first std::ranges::shift_left(b, 8);// ditto std::ranges::shift_left(c, 8);// dittostd::cout<< a <<" "<< b <<" "<< c <<'\n'; // std::ranges::shift_left(a, -3); // UB}
Possible output:
vector<S> vector<int> vector<string> 1 2 3 4 5 6 7 1 2 3 4 5 6 7 α β γ δ ε ζ η 4 5 6 7 . . . 4 5 6 7 5 6 7 δ ε ζ η . . . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η .
[edit]See also
(C++20) | moves a range of elements to a new location (algorithm function object) |
(C++20) | moves a range of elements to a new location in backwards order (algorithm function object) |
(C++20) | rotates the order of elements in a range (algorithm function object) |
(C++20) | shifts elements in a range (function template) |