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std::ranges::lexicographical_compare

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< cpp‎ | algorithm‎ | ranges
 
 
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Defined in header <algorithm>
Call signature
template<std::input_iterator I1, std::sentinel_for<I1> S1,

          std::input_iterator I2, std::sentinel_for<I2> S2,
          class Proj1 =std::identity, class Proj2 =std::identity,
          std::indirect_strict_weak_order<
              std::projected<I1, Proj1>,
              std::projected<I2, Proj2>> Comp =ranges::less>
constexprbool
    lexicographical_compare( I1 first1, S1 last1, I2 first2, S2 last2,

                             Comp comp ={}, Proj1 proj1 ={}, Proj2 proj2 ={});
(1) (since C++20)
template<ranges::input_range R1, ranges::input_range R2,

          class Proj1 =std::identity, class Proj2 =std::identity,
          std::indirect_strict_weak_order<
              std::projected<ranges::iterator_t<R1>, Proj1>,
              std::projected<ranges::iterator_t<R2>, Proj2>> Comp =ranges::less>
constexprbool
    lexicographical_compare( R1&& r1, R2&& r2, Comp comp ={},

                             Proj1 proj1 ={}, Proj2 proj2 ={});
(2) (since C++20)

Checks if the first range [first1last1) is lexicographically less than the second range [first2last2).

1) Elements are compared using the given binary comparison function comp.
2) Same as (1), but uses r as the source range, as if using ranges::begin(r) as first and ranges::end(r) as last.

Lexicographical comparison is an operation with the following properties:

  • Two ranges are compared element by element.
  • The first mismatching element defines which range is lexicographically less or greater than the other.
  • If one range is a prefix of another, the shorter range is lexicographically less than the other.
  • If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.
  • An empty range is lexicographically less than any non-empty range.
  • Two empty ranges are lexicographically equal.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

Contents

[edit]Parameters

first1, last1 - the iterator-sentinel pair defining the first range of elements to examine
r1 - the first range of elements to examine
first2, last2 - the iterator-sentinel pair defining the second range of elements to examine
r2 - the second range of elements to examine
comp - comparison function to apply to the projected elements
proj1 - projection to apply to the first range of elements
proj2 - projection to apply to the second range of elements

[edit]Return value

true if the first range is lexicographically less than the second.

[edit]Complexity

At most 2·min(N1, N2) applications of the comparison and corresponding projections, where N1 =ranges::distance(first1, last1) and N2 =ranges::distance(first2, last2).

[edit]Possible implementation

struct lexicographical_compare_fn {template<std::input_iterator I1, std::sentinel_for<I1> S1, std::input_iterator I2, std::sentinel_for<I2> S2, class Proj1 =std::identity, class Proj2 =std::identity, std::indirect_strict_weak_order< std::projected<I1, Proj1>, std::projected<I2, Proj2>> Comp =ranges::less>constexprbool operator()(I1 first1, S1 last1, I2 first2, S2 last2, Comp comp ={}, Proj1 proj1 ={}, Proj2 proj2 ={})const{for(;(first1 != last1)&&(first2 != last2);++first1, (void)++first2){if(std::invoke(comp, std::invoke(proj1, *first1), std::invoke(proj2, *first2)))returntrue;   if(std::invoke(comp, std::invoke(proj2, *first2), std::invoke(proj1, *first1)))returnfalse;}return(first1 == last1)&&(first2 != last2);}   template<ranges::input_range R1, ranges::input_range R2, class Proj1 =std::identity, class Proj2 =std::identity, std::indirect_strict_weak_order< std::projected<ranges::iterator_t<R1>, Proj1>, std::projected<ranges::iterator_t<R2>, Proj2>> Comp =ranges::less>constexprbool operator()(R1&& r1, R2&& r2, Comp comp ={}, Proj1 proj1 ={}, Proj2 proj2 ={})const{return(*this)(ranges::begin(r1), ranges::end(r1), ranges::begin(r2), ranges::end(r2), std::ref(comp), std::ref(proj1), std::ref(proj2));}};   inlineconstexpr lexicographical_compare_fn lexicographical_compare;

[edit]Example

#include <algorithm>#include <iostream>#include <iterator>#include <random>#include <vector>   int main(){std::vector<char> v1 {'a', 'b', 'c', 'd'};std::vector<char> v2 {'a', 'b', 'c', 'd'};   namespace ranges = std::ranges;auto os =std::ostream_iterator<char>(std::cout, " ");   std::mt19937 g {std::random_device{}()};while(not ranges::lexicographical_compare(v1, v2)){ranges::copy(v1, os);std::cout<<">= ";ranges::copy(v2, os);std::cout<<'\n';   ranges::shuffle(v1, g);ranges::shuffle(v2, g);}   ranges::copy(v1, os);std::cout<<"< ";ranges::copy(v2, os);std::cout<<'\n';}

Possible output:

a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b

[edit]See also

determines if two sets of elements are the same
(algorithm function object)[edit]
returns true if one range is lexicographically less than another
(function template)[edit]
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