std::ranges::lexicographical_compare
Defined in header <algorithm> | ||
Call signature | ||
template<std::input_iterator I1, std::sentinel_for<I1> S1, std::input_iterator I2, std::sentinel_for<I2> S2, | (1) | (since C++20) |
template<ranges::input_range R1, ranges::input_range R2, class Proj1 =std::identity, class Proj2 =std::identity, | (2) | (since C++20) |
Checks if the first range [
first1,
last1)
is lexicographically less than the second range [
first2,
last2)
.
Lexicographical comparison is an operation with the following properties:
- Two ranges are compared element by element.
- The first mismatching element defines which range is lexicographically less or greater than the other.
- If one range is a prefix of another, the shorter range is lexicographically less than the other.
- If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.
- An empty range is lexicographically less than any non-empty range.
- Two empty ranges are lexicographically equal.
The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:
- Explicit template argument lists cannot be specified when calling any of them.
- None of them are visible to argument-dependent lookup.
- When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.
Contents |
[edit]Parameters
first1, last1 | - | the iterator-sentinel pair defining the first range of elements to examine |
r1 | - | the first range of elements to examine |
first2, last2 | - | the iterator-sentinel pair defining the second range of elements to examine |
r2 | - | the second range of elements to examine |
comp | - | comparison function to apply to the projected elements |
proj1 | - | projection to apply to the first range of elements |
proj2 | - | projection to apply to the second range of elements |
[edit]Return value
true if the first range is lexicographically less than the second.
[edit]Complexity
At most 2·min(N1, N2) applications of the comparison and corresponding projections, where N1 =ranges::distance(first1, last1) and N2 =ranges::distance(first2, last2).
[edit]Possible implementation
struct lexicographical_compare_fn {template<std::input_iterator I1, std::sentinel_for<I1> S1, std::input_iterator I2, std::sentinel_for<I2> S2, class Proj1 =std::identity, class Proj2 =std::identity, std::indirect_strict_weak_order< std::projected<I1, Proj1>, std::projected<I2, Proj2>> Comp =ranges::less>constexprbool operator()(I1 first1, S1 last1, I2 first2, S2 last2, Comp comp ={}, Proj1 proj1 ={}, Proj2 proj2 ={})const{for(;(first1 != last1)&&(first2 != last2);++first1, (void)++first2){if(std::invoke(comp, std::invoke(proj1, *first1), std::invoke(proj2, *first2)))returntrue; if(std::invoke(comp, std::invoke(proj2, *first2), std::invoke(proj1, *first1)))returnfalse;}return(first1 == last1)&&(first2 != last2);} template<ranges::input_range R1, ranges::input_range R2, class Proj1 =std::identity, class Proj2 =std::identity, std::indirect_strict_weak_order< std::projected<ranges::iterator_t<R1>, Proj1>, std::projected<ranges::iterator_t<R2>, Proj2>> Comp =ranges::less>constexprbool operator()(R1&& r1, R2&& r2, Comp comp ={}, Proj1 proj1 ={}, Proj2 proj2 ={})const{return(*this)(ranges::begin(r1), ranges::end(r1), ranges::begin(r2), ranges::end(r2), std::ref(comp), std::ref(proj1), std::ref(proj2));}}; inlineconstexpr lexicographical_compare_fn lexicographical_compare; |
[edit]Example
#include <algorithm>#include <iostream>#include <iterator>#include <random>#include <vector> int main(){std::vector<char> v1 {'a', 'b', 'c', 'd'};std::vector<char> v2 {'a', 'b', 'c', 'd'}; namespace ranges = std::ranges;auto os =std::ostream_iterator<char>(std::cout, " "); std::mt19937 g {std::random_device{}()};while(not ranges::lexicographical_compare(v1, v2)){ranges::copy(v1, os);std::cout<<">= ";ranges::copy(v2, os);std::cout<<'\n'; ranges::shuffle(v1, g);ranges::shuffle(v2, g);} ranges::copy(v1, os);std::cout<<"< ";ranges::copy(v2, os);std::cout<<'\n';}
Possible output:
a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b
[edit]See also
(C++20) | determines if two sets of elements are the same (algorithm function object) |
returns true if one range is lexicographically less than another (function template) |