std::copy, std::copy_if
Defined in header <algorithm> | ||
template<class InputIt, class OutputIt > OutputIt copy( InputIt first, InputIt last, | (1) | (constexpr since C++20) |
template<class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > | (2) | (since C++17) |
template<class InputIt, class OutputIt, class UnaryPred > OutputIt copy_if( InputIt first, InputIt last, | (3) | (since C++11) (constexpr since C++20) |
template<class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class UnaryPred > | (4) | (since C++17) |
Copies the elements in the range, defined by [
first,
last)
, to another range beginning at d_first (copy destination range).
[
first,
last)
starting from first and proceeding to last.[
first,
last)
, the behavior is undefined. In this case, std::copy_backward may be used instead.std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. | (until C++20) |
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. | (since C++20) |
[
first,
last)
and the copy destination range overlaps, the behavior is undefined.[
first,
last)
and the copy destination range overlaps, the behavior is undefined.std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. | (until C++20) |
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. | (since C++20) |
Contents |
[edit]Parameters
first, last | - | the pair of iterators defining the source range of elements to copy |
d_first | - | the beginning of the destination range |
policy | - | the execution policy to use |
pred | - | unary predicate which returns true for the required elements. The expression pred(v) must be convertible to bool for every argument |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator. | ||
-OutputIt must meet the requirements of LegacyOutputIterator. | ||
-ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. | ||
-UnaryPred must meet the requirements of Predicate. |
[edit]Return value
Output iterator to the element in the destination range, one past the last element copied.
[edit]Complexity
Given N as std::distance(first, last):
For the overloads with an ExecutionPolicy
, there may be a performance cost if ForwardIt1
's value type is not MoveConstructible.
[edit]Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit]Possible implementation
copy (1) |
---|
template<class InputIt, class OutputIt> OutputIt copy(InputIt first, InputIt last, OutputIt d_first){for(; first != last;(void)++first, (void)++d_first)*d_first =*first; return d_first;} |
copy_if (3) |
template<class InputIt, class OutputIt, class UnaryPred> OutputIt copy_if(InputIt first, InputIt last, OutputIt d_first, UnaryPred pred){for(; first != last;++first)if(pred(*first)){*d_first =*first;++d_first;} return d_first;} |
[edit]Notes
In practice, implementations of std::copy
avoid multiple assignments and use bulk copy functions such as std::memmove if the value type is TriviallyCopyable and the iterator types satisfy LegacyContiguousIterator.
When copying overlapping ranges, std::copy
is appropriate when copying to the left (beginning of the destination range is outside the source range) while std::copy_backward
is appropriate when copying to the right (end of the destination range is outside the source range).
[edit]Example
The following code uses std::copy
both to copy the contents of one std::vector to another and to display the resulting std::vector.
#include <algorithm>#include <iostream>#include <iterator>#include <numeric>#include <vector> int main(){std::vector<int> from_vector(10);std::iota(from_vector.begin(), from_vector.end(), 0);std::vector<int> to_vector; std::copy(from_vector.begin(), from_vector.end(), std::back_inserter(to_vector)); // or, alternatively,// std::vector<int> to_vector(from_vector.size());// std::copy(from_vector.begin(), from_vector.end(), to_vector.begin());// either way is equivalent to// std::vector<int> to_vector = from_vector; std::cout<<"to_vector contains: "; std::copy(to_vector.begin(), to_vector.end(), std::ostream_iterator<int>(std::cout, " "));std::cout<<'\n'; std::cout<<"odd numbers in to_vector are: "; std::copy_if(to_vector.begin(), to_vector.end(), std::ostream_iterator<int>(std::cout, " "), [](int x){return x %2!=0;});std::cout<<'\n'; std::cout<<"to_vector contains these multiples of 3: "; to_vector.clear(); std::copy_if(from_vector.begin(), from_vector.end(), std::back_inserter(to_vector), [](int x){return x %3==0;}); for(constint x : to_vector)std::cout<< x <<' ';std::cout<<'\n';}
Possible output:
to_vector contains: 0 1 2 3 4 5 6 7 8 9 odd numbers in to_vector are: 1 3 5 7 9 to_vector contains these multiples of 3: 0 3 6 9
[edit]Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2039 | C++11 | the return value of std::copy_if was not specified | specified |
LWG 2044 | C++11 | the stability of std::copy_if was not defined | defined |
[edit]See also
copies a range of elements in backwards order (function template) | |
creates a copy of a range that is reversed (function template) | |
(C++11) | copies a number of elements to a new location (function template) |
copy-assigns the given value to every element in a range (function template) | |
copies a range of elements omitting those that satisfy specific criteria (function template) | |
(C++20)(C++20) | copies a range of elements to a new location (algorithm function object) |