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std::for_each

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< cpp‎ | algorithm
 
 
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Defined in header <algorithm>
template<class InputIt, class UnaryFunc >
UnaryFunc for_each( InputIt first, InputIt last, UnaryFunc f );
(1)(constexpr since C++20)
template<class ExecutionPolicy, class ForwardIt, class UnaryFunc >

void for_each( ExecutionPolicy&& policy,

               ForwardIt first, ForwardIt last, UnaryFunc f );
(2)(since C++17)

Applies the given unary function objectf to the result of dereferencing every iterator in the range[firstlast). If f returns a result, the result is ignored.

1)f is applied in order starting from first.

If UnaryFunc is not MoveConstructible, the behavior is undefined.

(since C++11)
2)f might not be applied in order. The algorithm is executed according to policy.
This overload participates in overload resolution only if all following conditions are satisfied:

std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true.

(until C++20)

std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true.

(since C++20)
If UnaryFunc is not CopyConstructible, the behavior is undefined.

If the iterator type (InputIt/ForwardIt) is mutable, f may modify the elements of the range through the dereferenced iterator.

Unlike the rest of the parallel algorithms, for_each is not allowed to make copies of the elements in the sequence even if they are TriviallyCopyable.

Contents

[edit]Parameters

first, last - the pair of iterators defining the range of elements to which the function object will be applied
policy - the execution policy to use
f - function object, to be applied to the result of dereferencing every iterator in the range[firstlast)

The signature of the function should be equivalent to the following:

 void fun(const Type &a);

The signature does not need to have const&.
The type  Type must be such that an object of type InputIt can be dereferenced and then implicitly converted to  Type.

Type requirements
-
InputIt must meet the requirements of LegacyInputIterator.
-
ForwardIt must meet the requirements of LegacyForwardIterator.

[edit]Return value

1)f
2) (none)

[edit]Complexity

Exactly std::distance(first, last) applications of f.

[edit]Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

  • If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
  • If the algorithm fails to allocate memory, std::bad_alloc is thrown.

[edit]Possible implementation

See also the implementations in libstdc++, libc++ and MSVC stdlib.

template<class InputIt, class UnaryFunc>constexpr UnaryFunc for_each(InputIt first, InputIt last, UnaryFunc f){for(; first != last;++first) f(*first);   return f;// implicit move since C++11}

[edit]Notes

For overload (1), f can be a stateful function object. The return value can be considered as the final state of the batch operation.

For overload (2), multiple copies of f may be created to perform parallel invocation. No value is returned because parallelization often does not permit efficient state accumulation.

[edit]Example

The following example uses a lambda-expression to increment all of the elements of a vector and then uses an overloaded operator() in a function object (i.k.a., "functor") to compute their sum. Note that to compute the sum, it is recommended to use the dedicated algorithm std::accumulate.

#include <algorithm>#include <iostream>#include <vector>   int main(){std::vector<int> v{3, -4, 2, -8, 15, 267};   auto print =[](constint& n){std::cout<< n <<' ';};   std::cout<<"before:\t"; std::for_each(v.cbegin(), v.cend(), print);std::cout<<'\n';   // increment elements in-place std::for_each(v.begin(), v.end(), [](int&n){ n++;});   std::cout<<"after:\t"; std::for_each(v.cbegin(), v.cend(), print);std::cout<<'\n';   struct Sum {void operator()(int n){ sum += n;}int sum {0};};   // invoke Sum::operator() for each element Sum s = std::for_each(v.cbegin(), v.cend(), Sum());std::cout<<"sum:\t"<< s.sum<<'\n';}

Output:

before: 3 -4 2 -8 15 267 after: 4 -3 3 -7 16 268 sum: 281

[edit]Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 475C++98 it was unclear whether f can modify the elements
of the sequence being iterated over (for_each is
classified as “non-modifying sequence operations”)
made clear (allowed if the
iterator type is mutable)
LWG 2747C++11 overload (1) returned std::move(f)returns f (which implicitly moves)

[edit]See also

applies a function to a range of elements, storing results in a destination range
(function template)[edit]
(C++17)
applies a function object to the first N elements of a sequence
(function template)[edit]
applies a unary function object to elements from a range
(algorithm function object)[edit]
applies a function object to the first N elements of a sequence
(algorithm function object)[edit]
range-for loop(C++11) executes loop over range[edit]
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