std::for_each
Defined in header <algorithm> | ||
template<class InputIt, class UnaryFunc > UnaryFunc for_each( InputIt first, InputIt last, UnaryFunc f ); | (1) | (constexpr since C++20) |
template<class ExecutionPolicy, class ForwardIt, class UnaryFunc > void for_each( ExecutionPolicy&& policy, | (2) | (since C++17) |
Applies the given unary function objectf to the result of dereferencing every iterator in the range[
first,
last)
. If f returns a result, the result is ignored.
If | (since C++11) |
std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. | (until C++20) |
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. | (since C++20) |
If the iterator type (InputIt
/ForwardIt
) is mutable, f may modify the elements of the range through the dereferenced iterator.
Unlike the rest of the parallel algorithms, for_each
is not allowed to make copies of the elements in the sequence even if they are TriviallyCopyable.
Contents |
[edit]Parameters
first, last | - | the pair of iterators defining the range of elements to which the function object will be applied |
policy | - | the execution policy to use |
f | - | function object, to be applied to the result of dereferencing every iterator in the range[ first, last) The signature of the function should be equivalent to the following: void fun(const Type &a); The signature does not need to have const&. |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator. | ||
-ForwardIt must meet the requirements of LegacyForwardIterator. |
[edit]Return value
[edit]Complexity
Exactly std::distance(first, last) applications of f.
[edit]Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit]Possible implementation
See also the implementations in libstdc++, libc++ and MSVC stdlib.
template<class InputIt, class UnaryFunc>constexpr UnaryFunc for_each(InputIt first, InputIt last, UnaryFunc f){for(; first != last;++first) f(*first); return f;// implicit move since C++11} |
[edit]Notes
For overload (1), f can be a stateful function object. The return value can be considered as the final state of the batch operation.
For overload (2), multiple copies of f may be created to perform parallel invocation. No value is returned because parallelization often does not permit efficient state accumulation.
[edit]Example
The following example uses a lambda-expression to increment all of the elements of a vector and then uses an overloaded operator()
in a function object (i.k.a., "functor") to compute their sum. Note that to compute the sum, it is recommended to use the dedicated algorithm std::accumulate.
#include <algorithm>#include <iostream>#include <vector> int main(){std::vector<int> v{3, -4, 2, -8, 15, 267}; auto print =[](constint& n){std::cout<< n <<' ';}; std::cout<<"before:\t"; std::for_each(v.cbegin(), v.cend(), print);std::cout<<'\n'; // increment elements in-place std::for_each(v.begin(), v.end(), [](int&n){ n++;}); std::cout<<"after:\t"; std::for_each(v.cbegin(), v.cend(), print);std::cout<<'\n'; struct Sum {void operator()(int n){ sum += n;}int sum {0};}; // invoke Sum::operator() for each element Sum s = std::for_each(v.cbegin(), v.cend(), Sum());std::cout<<"sum:\t"<< s.sum<<'\n';}
Output:
before: 3 -4 2 -8 15 267 after: 4 -3 3 -7 16 268 sum: 281
[edit]Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 475 | C++98 | it was unclear whether f can modify the elements of the sequence being iterated over ( for_each isclassified as “non-modifying sequence operations”) | made clear (allowed if the iterator type is mutable) |
LWG 2747 | C++11 | overload (1) returned std::move(f) | returns f (which implicitly moves) |
[edit]See also
applies a function to a range of elements, storing results in a destination range (function template) | |
(C++17) | applies a function object to the first N elements of a sequence (function template) |
(C++20) | applies a unary function object to elements from a range (algorithm function object) |
(C++20) | applies a function object to the first N elements of a sequence (algorithm function object) |
range-for loop(C++11) | executes loop over range |