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std::ranges::move, std::ranges::move_result

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< cpp‎ | algorithm‎ | ranges
 
 
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All names in this menu belong to namespace std::ranges
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Defined in header <algorithm>
Call signature
template<std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O >

requires std::indirectly_movable<I, O>
constexpr move_result<I, O>

    move( I first, S last, O result );
(1) (since C++20)
template<ranges::input_range R, std::weakly_incrementable O >

requires std::indirectly_movable<ranges::iterator_t<R>, O>
constexpr move_result<ranges::borrowed_iterator_t<R>, O>

    move( R&& r, O result );
(2) (since C++20)
Helper types
template<class I, class O >
using move_result =ranges::in_out_result<I, O>;
(3) (since C++20)
1) Moves the elements in the range, defined by [firstlast), to another range beginning at result. The behavior is undefined if result is within the range [firstlast). In such a case, ranges::move_backward may be used instead.
2) Same as (1), but uses r as the source range, as if using ranges::begin(r) as first, and ranges::end(r) as last.

The elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

Contents

[edit]Parameters

first, last - the iterator-sentinel pair defining the range of elements to move
r - the range of the elements to move
result - the beginning of the destination range

[edit]Return value

{last, result + N}, where

1)N =ranges::distance(first, last).

[edit]Complexity

Exactly N move assignments.

[edit]Notes

When moving overlapping ranges, ranges::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while ranges::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

[edit]Possible implementation

struct move_fn {template<std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O> requires std::indirectly_movable<I, O>constexpr ranges::move_result<I, O> operator()(I first, S last, O result)const{for(; first != last;++first, ++result)*result =ranges::iter_move(first);return{std::move(first), std::move(result)};}template<ranges::input_range R, std::weakly_incrementable O> requires std::indirectly_movable<ranges::iterator_t<R>, O>constexpr ranges::move_result<ranges::borrowed_iterator_t<R>, O> operator()(R&& r, O result)const{return(*this)(ranges::begin(r), ranges::end(r), std::move(result));}};   inlineconstexpr move_fn move {};

[edit]Example

The following code moves thread objects (which themselves are non copyable) from one container to another.

#include <algorithm>#include <chrono>#include <iostream>#include <iterator>#include <list>#include <thread>#include <vector>usingnamespace std::literals::chrono_literals;   void f(std::chrono::milliseconds n){std::this_thread::sleep_for(n);std::cout<<"thread with n="<< n.count()<<"ms ended"<<std::endl;}   int main(){std::vector<std::jthread> v; v.emplace_back(f, 400ms); v.emplace_back(f, 600ms); v.emplace_back(f, 800ms);   std::list<std::jthread> l;   // std::ranges::copy() would not compile, because std::jthread is non-copyable std::ranges::move(v, std::back_inserter(l));}

Output:

thread with n=400ms ended thread with n=600ms ended thread with n=800ms ended

[edit]See also

moves a range of elements to a new location in backwards order
(algorithm function object)[edit]
copies a range of elements to a new location
(algorithm function object)[edit]
copies a range of elements in backwards order
(algorithm function object)[edit]
(C++11)
moves a range of elements to a new location
(function template)[edit]
(C++11)
converts the argument to an xvalue
(function template)[edit]
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