std::shift_left, std::shift_right
Defined in header <algorithm> | ||
template<class ForwardIt > constexpr ForwardIt shift_left( ForwardIt first, ForwardIt last, | (1) | (since C++20) |
template<class ExecutionPolicy, class ForwardIt > ForwardIt shift_left( ExecutionPolicy&& policy, | (2) | (since C++20) |
template<class ForwardIt > constexpr ForwardIt shift_right( ForwardIt first, ForwardIt last, | (3) | (since C++20) |
template<class ExecutionPolicy, class ForwardIt > ForwardIt shift_right( ExecutionPolicy&& policy, | (4) | (since C++20) |
Shifts the elements in the range [
first,
last)
by n positions.
- If n ==0|| n >= last - first, there are no effects.
- Otherwise, for every integer i in
[
0,
last - first - n)
, moves the element originally at position first + n + i to position first + i.
i
starting from 0.- If n ==0|| n >= last - first, there are no effects.
- Otherwise, for every integer i in
[
0,
last - first - n)
, moves the element originally at position first + i to position first + n + i.
ForwardIt
meets the LegacyBidirectionalIterator requirements, then the moves are performed in decreasing order of i starting from last - first - n -1.Elements that are in the original range but not the new range are left in a valid but unspecified state.
If any of the following conditions is satisfied, the behavior is undefined:
- n >=0 is not true.
- The type of *first is not MoveAssignable.
- For
shift_right
,ForwardIt
is neither LegacyBidirectionalIterator nor ValueSwappable.
Contents |
[edit]Parameters
first, last | - | the pair of iterators defining the range of elements to shift |
n | - | the number of positions to shift |
policy | - | the execution policy to use |
Type requirements | ||
-ForwardIt must meet the requirements of LegacyForwardIterator. |
[edit]Return value
- If n is less than std::distance(first, last), returns an iterator equal to std::next(first, (std::distance(first, last)- n)).
- Otherwise, returns first.
- If n is less than std::distance(first, last), returns an iterator equal to std::next(first, n).
- Otherwise, returns last.
[edit]Complexity
[edit]Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit]Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_shift | 201806L | (C++20) | std::shift_left and std::shift_right |
[edit]Example
#include <algorithm>#include <iostream>#include <string>#include <type_traits>#include <vector> struct S {int value{0};bool specified_state{true}; S(int v =0): value{v}{} S(S const& rhs)=default; S(S&& rhs){*this = std::move(rhs);} S& operator=(S const& rhs)=default; S& operator=(S&& rhs){if(this !=&rhs){ value = rhs.value; specified_state = rhs.specified_state; rhs.specified_state=false;}return*this;}}; template<typename T>std::ostream& operator<<(std::ostream& os, std::vector<T>const& v){for(constauto& s : v){ifconstexpr(std::is_same_v<T, S>) s.specified_state? os << s.value<<' ': os <<". ";elseifconstexpr(std::is_same_v<T, std::string>) os <<(s.empty()?".": s)<<' ';else os << s <<' ';}return os;} int main(){std::cout<<std::left; std::vector<S> a{1, 2, 3, 4, 5, 6, 7};std::vector<int> b{1, 2, 3, 4, 5, 6, 7};std::vector<std::string> c{"α", "β", "γ", "δ", "ε", "ζ", "η"}; std::cout<<"vector<S> \tvector<int> \tvector<string>\n";std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::shift_left(begin(a), end(a), 3); std::shift_left(begin(b), end(b), 3); std::shift_left(begin(c), end(c), 3);std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::shift_right(begin(a), end(a), 2); std::shift_right(begin(b), end(b), 2); std::shift_right(begin(c), end(c), 2);std::cout<< a <<" "<< b <<" "<< c <<'\n'; std::shift_left(begin(a), end(a), 8);// has no effect: n >= last - first std::shift_left(begin(b), end(b), 8);// ditto std::shift_left(begin(c), end(c), 8);// dittostd::cout<< a <<" "<< b <<" "<< c <<'\n'; // std::shift_left(begin(a), end(a), -3); // UB, e.g. segfault}
Possible output:
vector<S> vector<int> vector<string> 1 2 3 4 5 6 7 1 2 3 4 5 6 7 α β γ δ ε ζ η 4 5 6 7 . . . 4 5 6 7 5 6 7 δ ε ζ η . . . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η . . . 4 5 6 7 . 4 5 4 5 6 7 5 . . δ ε ζ η .
[edit]See also
(C++11) | moves a range of elements to a new location (function template) |
(C++11) | moves a range of elements to a new location in backwards order (function template) |
rotates the order of elements in a range (function template) | |
shifts elements in a range (algorithm function object) |