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std::move_backward

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Defined in header <algorithm>
template<class BidirIt1, class BidirIt2 >
BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last );
(since C++11)
(constexpr since C++20)

Moves the elements from the range [firstlast), to another range ending at d_last. The elements are moved in reverse order (the last element is moved first), but their relative order is preserved.

If d_last is within (firstlast], the behavior is undefined. In this case, std::move may be used instead.

Contents

[edit]Parameters

first, last - the pair of iterators defining the source range of elements to move
d_last - end of the destination range
Type requirements
-
BidirIt1, BidirIt2 must meet the requirements of LegacyBidirectionalIterator.

[edit]Return value

Iterator in the destination range, pointing at the last element moved.

[edit]Complexity

Exactly std::distance(first, last) move assignments.

[edit]Possible implementation

template<class BidirIt1, class BidirIt2> BidirIt2 move_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last){while(first != last)*(--d_last)= std::move(*(--last));   return d_last;}

[edit]Notes

When moving overlapping ranges, std::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

[edit]Example

#include <algorithm>#include <iostream>#include <iterator>#include <string>#include <string_view>#include <vector>   using container =std::vector<std::string>;   void print(std::string_view comment, const container& src, const container& dst ={}){auto prn =[](std::string_view name, const container& cont){std::cout<< name;for(constauto&s : cont)std::cout<<(s.empty()?"∙": s.data())<<' ';std::cout<<'\n';};std::cout<< comment <<'\n'; prn("src: ", src);if(dst.empty())return; prn("dst: ", dst);}   int main(){ container src{"foo", "bar", "baz"}; container dst{"qux", "quux", "quuz", "corge"}; print("Non-overlapping case; before move_backward:", src, dst); std::move_backward(src.begin(), src.end(), dst.end()); print("After:", src, dst);   src ={"snap", "crackle", "pop", "lock", "drop"}; print("Overlapping case; before move_backward:", src); std::move_backward(src.begin(), std::next(src.begin(), 3), src.end()); print("After:", src);}

Output:

Non-overlapping case; before move_backward: src: foo bar baz dst: qux quux quuz corge After: src: ∙ ∙ ∙ dst: qux foo bar baz Overlapping case; before move_backward: src: snap crackle pop lock drop After: src: ∙ ∙ snap crackle pop

[edit]See also

(C++11)
moves a range of elements to a new location
(function template)[edit]
moves a range of elements to a new location in backwards order
(algorithm function object)[edit]
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