std::move_backward
From cppreference.com
Defined in header <algorithm> | ||
template<class BidirIt1, class BidirIt2 > BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); | (since C++11) (constexpr since C++20) | |
Moves the elements from the range [
first,
last)
, to another range ending at d_last. The elements are moved in reverse order (the last element is moved first), but their relative order is preserved.
If d_last is within (
first,
last]
, the behavior is undefined. In this case, std::move
may be used instead.
Contents |
[edit]Parameters
first, last | - | the pair of iterators defining the source range of elements to move |
d_last | - | end of the destination range |
Type requirements | ||
-BidirIt1, BidirIt2 must meet the requirements of LegacyBidirectionalIterator. |
[edit]Return value
Iterator in the destination range, pointing at the last element moved.
[edit]Complexity
Exactly std::distance(first, last) move assignments.
[edit]Possible implementation
template<class BidirIt1, class BidirIt2> BidirIt2 move_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last){while(first != last)*(--d_last)= std::move(*(--last)); return d_last;} |
[edit]Notes
When moving overlapping ranges, std::move
is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward
is appropriate when moving to the right (end of the destination range is outside the source range).
[edit]Example
Run this code
#include <algorithm>#include <iostream>#include <iterator>#include <string>#include <string_view>#include <vector> using container =std::vector<std::string>; void print(std::string_view comment, const container& src, const container& dst ={}){auto prn =[](std::string_view name, const container& cont){std::cout<< name;for(constauto&s : cont)std::cout<<(s.empty()?"∙": s.data())<<' ';std::cout<<'\n';};std::cout<< comment <<'\n'; prn("src: ", src);if(dst.empty())return; prn("dst: ", dst);} int main(){ container src{"foo", "bar", "baz"}; container dst{"qux", "quux", "quuz", "corge"}; print("Non-overlapping case; before move_backward:", src, dst); std::move_backward(src.begin(), src.end(), dst.end()); print("After:", src, dst); src ={"snap", "crackle", "pop", "lock", "drop"}; print("Overlapping case; before move_backward:", src); std::move_backward(src.begin(), std::next(src.begin(), 3), src.end()); print("After:", src);}
Output:
Non-overlapping case; before move_backward: src: foo bar baz dst: qux quux quuz corge After: src: ∙ ∙ ∙ dst: qux foo bar baz Overlapping case; before move_backward: src: snap crackle pop lock drop After: src: ∙ ∙ snap crackle pop
[edit]See also
(C++11) | moves a range of elements to a new location (function template) |
(C++20) | moves a range of elements to a new location in backwards order (algorithm function object) |