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std::invoke, std::invoke_r

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< cpp‎ | utility‎ | functional
 
 
 
Function objects
Function invocation
invokeinvoke_r
(C++17)(C++23)
Identity function object
(C++20)
Old binders and adaptors
(until C++17*)
(until C++17*)
(until C++17*)
(until C++17*)  
(until C++17*)
(until C++17*)(until C++17*)(until C++17*)(until C++17*)
(until C++20*)
(until C++20*)
(until C++17*)(until C++17*)
(until C++17*)(until C++17*)

(until C++17*)
(until C++17*)(until C++17*)(until C++17*)(until C++17*)
(until C++20*)
(until C++20*)
 
Defined in header <functional>
template<class F, class... Args>

std::invoke_result_t<F, Args...>

    invoke( F&& f, Args&&... args)noexcept(/* see below */);
(1)(since C++17)
(constexpr since C++20)
template<class R, class F, class... Args>

constexpr R

    invoke_r( F&& f, Args&&... args)noexcept(/* see below */);
(2)(since C++23)
1) Invoke the Callable object f with the parameters args as by INVOKE(std::forward<F>(f), std::forward<Args>(args)...). This overload participates in overload resolution only if std::is_invocable_v<F, Args...> is true.
2) Invoke the Callable object f with the parameters args as by INVOKE<R>(std::forward<F>(f), std::forward<Args>(args)...). This overload participates in overload resolution only if std::is_invocable_r_v<R, F, Args...> is true.

Contents

[edit]Parameters

f - Callable object to be invoked
args - arguments to pass to f

[edit]Return value

1) The value returned by f.
2) The value returned by f, implicitly converted to R, if R is not (possibly cv-qualified) void. None otherwise.

[edit]Exceptions

1)
noexcept specification:  
noexcept(std::is_nothrow_invocable_v<F, Args...>)
2)
noexcept specification:  
noexcept(std::is_nothrow_invocable_r_v<R, F, Args...>)

[edit]Possible implementation

invoke (1)
namespace detail {template<class>constexprbool is_reference_wrapper_v =false;template<class U>constexprbool is_reference_wrapper_v<std::reference_wrapper<U>>=true;   template<class T>using remove_cvref_t =std::remove_cv_t<std::remove_reference_t<T>>;   template<class C, class Pointed, class Object, class... Args>constexpr decltype(auto) invoke_memptr(Pointed C::* member, Object&& object, Args&&... args){using object_t = remove_cvref_t<Object>;constexprbool is_member_function =std::is_function_v<Pointed>;constexprbool is_wrapped = is_reference_wrapper_v<object_t>;constexprbool is_derived_object =std::is_same_v<C, object_t>||std::is_base_of_v<C, object_t>;   ifconstexpr(is_member_function){ifconstexpr(is_derived_object)return(std::forward<Object>(object) .* member)(std::forward<Args>(args)...);elseifconstexpr(is_wrapped)return(object.get() .* member)(std::forward<Args>(args)...);elsereturn((*std::forward<Object>(object)) .* member)(std::forward<Args>(args)...);}else{ static_assert(std::is_object_v<Pointed>&& sizeof...(args)==0);ifconstexpr(is_derived_object)returnstd::forward<Object>(object) .* member;elseifconstexpr(is_wrapped)return object.get() .* member;elsereturn(*std::forward<Object>(object)) .* member;}}}// namespace detail   template<class F, class... Args>constexprstd::invoke_result_t<F, Args...> invoke(F&& f, Args&&... args)noexcept(std::is_nothrow_invocable_v<F, Args...>){ifconstexpr(std::is_member_pointer_v<detail::remove_cvref_t<F>>)return detail::invoke_memptr(f, std::forward<Args>(args)...);elsereturnstd::forward<F>(f)(std::forward<Args>(args)...);}
invoke_r (2)
template<class R, class F, class... Args> requires std::is_invocable_r_v<R, F, Args...>constexpr R invoke_r(F&& f, Args&&... args)noexcept(std::is_nothrow_invocable_r_v<R, F, Args...>){ifconstexpr(std::is_void_v<R>) std::invoke(std::forward<F>(f), std::forward<Args>(args)...);elsereturn std::invoke(std::forward<F>(f), std::forward<Args>(args)...);}

[edit]Notes

Feature-test macro ValueStdFeature
__cpp_lib_invoke201411L(C++17)std::invoke, (1)
__cpp_lib_invoke_r202106L(C++23)std::invoke_r, (2)

[edit]Example

#include <functional>#include <iostream>#include <type_traits>   struct Foo { Foo(int num): num_(num){}void print_add(int i)const{std::cout<< num_ + i <<'\n';}int num_;};   void print_num(int i){std::cout<< i <<'\n';}   struct PrintNum {void operator()(int i)const{std::cout<< i <<'\n';}};   int main(){std::cout<<"invoke a free function: "; std::invoke(print_num, -9);   std::cout<<"invoke a lambda: "; std::invoke([](){ print_num(42);});   std::cout<<"invoke a member function: ";const Foo foo(314159); std::invoke(&Foo::print_add, foo, 1);   std::cout<<"invoke (i.e., access) a data member num_: "<< std::invoke(&Foo::num_, foo)<<'\n';   std::cout<<"invoke a function object: "; std::invoke(PrintNum(), 18);   #if defined(__cpp_lib_invoke_r)auto add =[](int x, int y){return x + y;};std::cout<<"invoke a lambda converting result to float: ";auto ret = std::invoke_r<float>(add, 11, 22); static_assert(std::is_same<decltype(ret), float>());std::cout<<std::fixed<< ret <<"\ninvoke print_num: "; std::invoke_r<void>(print_num, 44);#endif}

Possible output:

invoke a free function: -9 invoke a lambda: 42 invoke a member function: 314160 invoke (i.e., access) a data member num_: 314159 invoke a function object: 18 invoke a lambda converting result to float: 33.000000 invoke print_num: 44

[edit]See also

(C++11)
creates a function object out of a pointer to a member
(function template)[edit]
(C++11)(removed in C++20)(C++17)
deduces the result type of invoking a callable object with a set of arguments
(class template)[edit]
checks if a type can be invoked (as if by std::invoke) with the given argument types
(class template)[edit]
(C++17)
calls a function with a tuple of arguments
(function template)[edit]
close