std::invoke, std::invoke_r
From cppreference.com
< cpp | utility | functional
Defined in header <functional> | ||
template<class F, class... Args> std::invoke_result_t<F, Args...> | (1) | (since C++17) (constexpr since C++20) |
template<class R, class F, class... Args> constexpr R | (2) | (since C++23) |
1) Invoke the Callable object f with the parameters args as by
INVOKE
(std::forward<F>(f), std::forward<Args>(args)...). This overload participates in overload resolution only if std::is_invocable_v<F, Args...> is true.2) Invoke the Callable object f with the parameters args as by
INVOKE<R>
(std::forward<F>(f), std::forward<Args>(args)...). This overload participates in overload resolution only if std::is_invocable_r_v<R, F, Args...> is true.Contents |
[edit]Parameters
f | - | Callable object to be invoked |
args | - | arguments to pass to f |
[edit]Return value
1) The value returned by f.
2) The value returned by f, implicitly converted to
R
, if R
is not (possibly cv-qualified) void. None otherwise.[edit]Exceptions
1)
noexcept specification:
noexcept(std::is_nothrow_invocable_v<F, Args...>)
2)
noexcept specification:
noexcept(std::is_nothrow_invocable_r_v<R, F, Args...>)
[edit]Possible implementation
invoke (1) |
---|
namespace detail {template<class>constexprbool is_reference_wrapper_v =false;template<class U>constexprbool is_reference_wrapper_v<std::reference_wrapper<U>>=true; template<class T>using remove_cvref_t =std::remove_cv_t<std::remove_reference_t<T>>; template<class C, class Pointed, class Object, class... Args>constexpr decltype(auto) invoke_memptr(Pointed C::* member, Object&& object, Args&&... args){using object_t = remove_cvref_t<Object>;constexprbool is_member_function =std::is_function_v<Pointed>;constexprbool is_wrapped = is_reference_wrapper_v<object_t>;constexprbool is_derived_object =std::is_same_v<C, object_t>||std::is_base_of_v<C, object_t>; ifconstexpr(is_member_function){ifconstexpr(is_derived_object)return(std::forward<Object>(object) .* member)(std::forward<Args>(args)...);elseifconstexpr(is_wrapped)return(object.get() .* member)(std::forward<Args>(args)...);elsereturn((*std::forward<Object>(object)) .* member)(std::forward<Args>(args)...);}else{ static_assert(std::is_object_v<Pointed>&& sizeof...(args)==0);ifconstexpr(is_derived_object)returnstd::forward<Object>(object) .* member;elseifconstexpr(is_wrapped)return object.get() .* member;elsereturn(*std::forward<Object>(object)) .* member;}}}// namespace detail template<class F, class... Args>constexprstd::invoke_result_t<F, Args...> invoke(F&& f, Args&&... args)noexcept(std::is_nothrow_invocable_v<F, Args...>){ifconstexpr(std::is_member_pointer_v<detail::remove_cvref_t<F>>)return detail::invoke_memptr(f, std::forward<Args>(args)...);elsereturnstd::forward<F>(f)(std::forward<Args>(args)...);} |
invoke_r (2) |
template<class R, class F, class... Args> requires std::is_invocable_r_v<R, F, Args...>constexpr R invoke_r(F&& f, Args&&... args)noexcept(std::is_nothrow_invocable_r_v<R, F, Args...>){ifconstexpr(std::is_void_v<R>) std::invoke(std::forward<F>(f), std::forward<Args>(args)...);elsereturn std::invoke(std::forward<F>(f), std::forward<Args>(args)...);} |
[edit]Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_invoke | 201411L | (C++17) | std::invoke , (1) |
__cpp_lib_invoke_r | 202106L | (C++23) | std::invoke_r , (2) |
[edit]Example
Run this code
#include <functional>#include <iostream>#include <type_traits> struct Foo { Foo(int num): num_(num){}void print_add(int i)const{std::cout<< num_ + i <<'\n';}int num_;}; void print_num(int i){std::cout<< i <<'\n';} struct PrintNum {void operator()(int i)const{std::cout<< i <<'\n';}}; int main(){std::cout<<"invoke a free function: "; std::invoke(print_num, -9); std::cout<<"invoke a lambda: "; std::invoke([](){ print_num(42);}); std::cout<<"invoke a member function: ";const Foo foo(314159); std::invoke(&Foo::print_add, foo, 1); std::cout<<"invoke (i.e., access) a data member num_: "<< std::invoke(&Foo::num_, foo)<<'\n'; std::cout<<"invoke a function object: "; std::invoke(PrintNum(), 18); #if defined(__cpp_lib_invoke_r)auto add =[](int x, int y){return x + y;};std::cout<<"invoke a lambda converting result to float: ";auto ret = std::invoke_r<float>(add, 11, 22); static_assert(std::is_same<decltype(ret), float>());std::cout<<std::fixed<< ret <<"\ninvoke print_num: "; std::invoke_r<void>(print_num, 44);#endif}
Possible output:
invoke a free function: -9 invoke a lambda: 42 invoke a member function: 314160 invoke (i.e., access) a data member num_: 314159 invoke a function object: 18 invoke a lambda converting result to float: 33.000000 invoke print_num: 44
[edit]See also
(C++11) | creates a function object out of a pointer to a member (function template) |
(C++11)(removed in C++20)(C++17) | deduces the result type of invoking a callable object with a set of arguments (class template) |
checks if a type can be invoked (as if by std::invoke) with the given argument types (class template) | |
(C++17) | calls a function with a tuple of arguments (function template) |