std::remove_reference
From cppreference.com
Defined in header <type_traits> | ||
template<class T > struct remove_reference; | (since C++11) | |
If the type T
is a reference type, provides the member typedef type
which is the type referred to by T
. Otherwise type
is T
.
If the program adds specializations for std::remove_reference
, the behavior is undefined.
Contents |
[edit]Member types
Name | Definition |
type | the type referred by T or T if it is not a reference |
[edit]Helper types
template<class T > using remove_reference_t =typename remove_reference<T>::type; | (since C++14) | |
[edit]Possible implementation
template<class T>struct remove_reference {typedef T type;};template<class T>struct remove_reference<T&>{typedef T type;};template<class T>struct remove_reference<T&&>{typedef T type;}; |
[edit]Example
Run this code
#include <iostream>#include <type_traits> int main(){std::cout<<std::boolalpha; std::cout<<"std::remove_reference<int>::type is int? "<<std::is_same<int, std::remove_reference<int>::type>::value<<'\n';std::cout<<"std::remove_reference<int&>::type is int? "<<std::is_same<int, std::remove_reference<int&>::type>::value<<'\n';std::cout<<"std::remove_reference<int&&>::type is int? "<<std::is_same<int, std::remove_reference<int&&>::type>::value<<'\n';std::cout<<"std::remove_reference<const int&>::type is const int? "<<std::is_same<constint, std::remove_reference<constint&>::type>::value<<'\n';}
Output:
std::remove_reference<int>::type is int? true std::remove_reference<int&>::type is int? true std::remove_reference<int&&>::type is int? true std::remove_reference<const int&>::type is const int? true
[edit]See also
(C++11) | checks if a type is either an lvalue reference or rvalue reference (class template) |
(C++11)(C++11) | adds an lvalue or rvalue reference to the given type (class template) |
(C++20) | combines std::remove_cv and std::remove_reference (class template) |