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std::modulus

From cppreference.com
< cpp‎ | utility‎ | functional
 
 
 
Function objects
Function invocation
(C++17)(C++23)
Identity function object
(C++20)
Old binders and adaptors
(until C++17*)
(until C++17*)
(until C++17*)
(until C++17*)  
(until C++17*)
(until C++17*)(until C++17*)(until C++17*)(until C++17*)
(until C++20*)
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(until C++17*)(until C++17*)
(until C++17*)(until C++17*)

(until C++17*)
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Defined in header <functional>
template<class T >
struct modulus;
(until C++14)
template<class T =void>
struct modulus;
(since C++14)

Function object for computing remainders of divisions. Implements operator% for type T.

Contents

[edit]Specializations

The standard library provides a specialization of std::modulus when T is not specified, which leaves the parameter types and return type to be deduced.

function object implementing x % y deducing parameter and return types
(class template specialization)[edit]
(since C++14)

[edit]Member types

Type Definition
result_type(deprecated in C++17)(removed in C++20)T
first_argument_type(deprecated in C++17)(removed in C++20)T
second_argument_type(deprecated in C++17)(removed in C++20)T

These member types are obtained via publicly inheriting std::binary_function<T, T, T>.

(until C++11)

[edit]Member functions

operator()
returns the remainder from the division of the first argument by the second argument
(public member function)

std::modulus::operator()

T operator()(const T& lhs, const T& rhs )const;
(constexpr since C++14)

Returns the remainder of the division of lhs by rhs.

Parameters

lhs, rhs - values to divide one by another

Return value

The result of lhs % rhs.

[edit]Exceptions

May throw implementation-defined exceptions.

Possible implementation

constexpr T operator()(const T& lhs, const T& rhs)const{return lhs % rhs;}

[edit]See also

(C++11)(C++11)
remainder of the floating point division operation
(function)[edit]
(C++11)(C++11)(C++11)
signed remainder of the division operation
(function)[edit]
close