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std::function<R(Args...)>::target_type

From cppreference.com
< cpp‎ | utility‎ | functional‎ | function
 
 
 
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Function invocation
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conststd::type_info& target_type()constnoexcept;
(since C++11)

Returns the type of the stored function.

Contents

[edit]Parameters

(none)

[edit]Return value

typeid(T) if the stored function has type T, otherwise typeid(void)

[edit]Example

#include <functional>#include <iostream>   int f(int a){return-a;}void g(double){}int main(){// fn1 and fn2 have the same type, but their targets do notstd::function<int(int)> fn1(f), fn2([](int a){return-a;});std::cout<< fn1.target_type().name()<<'\n'<< fn2.target_type().name()<<'\n';   // since C++17 deduction guides (CTAD) can availstd::cout<<std::function{g}.target_type().name()<<'\n';}

Possible output:

PFiiE Z4mainEUliE_ PFvdE

[edit]See also

obtains a pointer to the stored target
(public member function)[edit]
contains some type’s information, the class returned by the typeid operator
(class)[edit]
typeid queries information of a type, returning a std::type_info object representing the type
(operator)
close