std::lexicographical_compare
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Definido no cabeçalho <algorithm> | ||
template<class InputIt1, class InputIt2 > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, | (1) | |
template<class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, | (2) | |
Verifica se o [first1, last1) primeira gama é lexicographically menos do que o [first2, last2) segunda faixa. A primeira versão utiliza operator< para comparar os elementos, a segunda versão utiliza a função de comparação dada
comp.Original:
Checks if the first range [first1, last1) is lexicographically less than the second range [first2, last2). The first version uses operator< to compare the elements, the second version uses the given comparison function
comp.The text has been machine-translated via Google Translate.
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Lexicographical comparação é uma operação com as seguintes propriedades:
Original:
Lexicographical comparison is a operation with the following properties:
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- Duas faixas são comparados elemento por elemento.Original:Two ranges are compared element by element.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - O elemento descasamento primeiro define qual faixa é lexicographically menos ou' maior que o outro.Original:The first mismatching element defines which range is lexicographically less or greater than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Se um intervalo é um prefixo de outro, mais curto intervalo é lexicographically menos do que o outro.Original:If one range is a prefix of another, the shorter range is lexicographically less than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Se duas cadeias têm elementos equivalentes e são do mesmo comprimento, então, as faixas são lexicographically igual.Original:If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Uma faixa vazia é lexicographically menos do que qualquer intervalo não vazio.Original:An empty range is lexicographically less than any non-empty range.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Duas faixas vazias são lexicographically' igual.Original:Two empty ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Índice |
[editar]Parâmetros
| first1, last1 | - | a primeira gama de elementos para examinar Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | o segundo intervalo de elementos para examinar Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const&, but the function must not modify the objects passed to it. |
| Type requirements | ||
-InputIt1, InputIt2 must meet the requirements of InputIterator. | ||
[editar]Valor de retorno
true se a primeira faixa é lexicographically' menos do que a segunda.
Original:
true if the first range is lexicographically less than the second.
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[editar]Complexidade
Na maioria das aplicações de 2·min(N1, N2) de a operação de comparação, onde N1 =std::distance(first1, last1) e N2 =std::distance(first2, last2).
Original:
At most 2·min(N1, N2) applications of the comparison operation, where N1 =std::distance(first1, last1) and N2 =std::distance(first2, last2).
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[editar]Possível implementação
| First version |
|---|
template<class InputIt1, class InputIt2>bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2){for(;(first1 != last1)&&(first2 != last2); first1++, first2++){if(*first1 <*first2)returntrue;if(*first2 <*first1)returnfalse;}return(first1 == last1)&&(first2 != last2);} |
| Second version |
template<class InputIt1, class InputIt2, class Compare>bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp){for(;(first1 != last1)&&(first2 != last2); first1++, first2++){if(comp(*first1, *first2))returntrue;if(comp(*first2, *first1))returnfalse;}return(first1 == last1)&&(first2 != last2);} |
[editar]Exemplo
#include <algorithm>#include <iostream>#include <vector>#include <cstdlib>#include <ctime> int main(){std::vector<char> v1 {'a', 'b', 'c', 'd'};std::vector<char> v2 {'a', 'b', 'c', 'd'}; std::srand(std::time(0));while(!std::lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())){for(auto c : v1)std::cout<< c <<' ';std::cout<<">= ";for(auto c : v2)std::cout<< c <<' ';std::cout<<'\n'; std::random_shuffle(v1.begin(), v1.end());std::random_shuffle(v2.begin(), v2.end());} for(auto c : v1)std::cout<< c <<' ';std::cout<<"< ";for(auto c : v2)std::cout<< c <<' ';std::cout<<'\n';}
Potencial saída:
a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b
