std::count, std::count_if
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Definido no cabeçalho <algorithm> | ||
template<class InputIt, class T > typename iterator_traits<InputIt>::difference_type | (1) | |
template<class InputIt, class UnaryPredicate > typename iterator_traits<InputIt>::difference_type | (2) | |
Retorna o número de elementos no intervalo
[first, last)
satisfazer critérios específicos. A primeira versão conta os elementos que são iguais para value
, a segunda versão conta com elementos para os quais predicado p
retornos true. Original:
Returns the number of elements in the range
[first, last)
satisfying specific criteria. The first version counts the elements that are equal to value
, the second version counts elements for which predicate p
returns true. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Índice |
[editar]Parâmetros
first, last | - | a gama de elementos para examinar Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
value | - | o valor a ser procurado Original: the value to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
p | - | unary predicate which returns true para os elementos necessários . Original: for the required elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const&, but the function must not modify the objects passed to it. |
Type requirements | ||
-InputIt must meet the requirements of InputIterator . |
[editar]Valor de retorno
número de elementos que satisfaz a condição.
Original:
number of elements satisfying the condition.
The text has been machine-translated via Google Translate.
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[editar]Complexidade
exatamente
last
- first
comparações / aplicações do predicadoOriginal:
exactly
last
- first
comparisons / applications of the predicateThe text has been machine-translated via Google Translate.
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[editar]Possível implementação
First version |
---|
template<class InputIt, class T>typename iterator_traits<InputIt>::difference_type count(InputIt first, InputIt last, const T& value){typename iterator_traits<InputIt>::difference_type ret =0;for(; first != last;++first){if(*first == value){ ret++;}}return ret;} |
Second version |
template<class InputIt, class UnaryPredicate>typename iterator_traits<InputIt>::difference_type count_if(InputIt first, InputIt last, UnaryPredicate p){typename iterator_traits<InputIt>::difference_type ret =0;for(; first != last;++first){if(p(*first)){ ret++;}}return ret;} |
[editar]Exemplo
O código a seguir usa
count
para determinar quantos números inteiros em uma std::vector corresponder a um valor alvo . Original:
The following code uses
count
to determine how many integers in a std::vector match a target value. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <algorithm>#include <iostream>#include <vector> int main(){int data[]={1, 2, 3, 4, 4, 3, 7, 8, 9, 10};std::vector<int> v(data, data+10); int target1 =3;int target2 =5;int num_items1 = std::count(v.begin(), v.end(), target1);int num_items2 = std::count(v.begin(), v.end(), target2); std::cout<<"number: "<< target1 <<" count: "<< num_items1 <<'\n';std::cout<<"number: "<< target2 <<" count: "<< num_items2 <<'\n';}
Saída:
number: 3 count: 2 number: 5 count: 0
Este exemplo usa um lambda expressão contar elementos divisível por 3 .
Original:
This example uses a lambda expressão to count elements divisible by 3.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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#include <algorithm>#include <iostream>#include <vector> int main(){int data[]={1, 2, 3, 4, 4, 3, 7, 8, 9, 10};std::vector<int> v(data, data+10); int num_items1 = std::count_if(v.begin(), v.end(), [](int i){return i %3==0;}); std::cout<<"number divisible by three: "<< num_items1 <<'\n';}
Saída:
number divisible by three: 3