std::swap(std::tuple)
From cppreference.com
Defined in header <tuple> | ||
(1) | ||
template<class... Types> void swap(std::tuple<Types...>& lhs, | (since C++11) (until C++20) | |
template<class... Types> constexprvoid swap(std::tuple<Types...>& lhs, | (since C++20) | |
template<class... Types> constexprvoid swap(conststd::tuple<Types...>& lhs, | (2) | (since C++23) |
Swaps the contents of lhs and rhs. Equivalent to lhs.swap(rhs).
1) This overload participates in overload resolution only if std::is_swappable_v<Ti> is true for all i from 0 to sizeof...(Types). 2) This overload participates in overload resolution only if std::is_swappable_v<const Ti> is true for all i from 0 to sizeof...(Types). | (since C++17) |
Contents |
[edit]Parameters
lhs, rhs | - | tuples whose contents to swap |
[edit]Return value
(none)
[edit]Exceptions
noexcept specification:
noexcept(noexcept(lhs.swap(rhs)))
[edit]Example
Run this code
#include <iostream>#include <string>#include <tuple> int main(){std::tuple<int, std::string, float> p1{42, "ABCD", 2.71}, p2; p2 =std::make_tuple(10, "1234", 3.14); auto print_p1_p2 =[&](auto rem){std::cout<< rem <<"p1 = {"<< std::get<0>(p1)<<", "<< std::get<1>(p1)<<", "<< std::get<2>(p1)<<"}, "<<"p2 = {"<< std::get<0>(p2)<<", "<< std::get<1>(p2)<<", "<< std::get<2>(p2)<<"}\n";}; print_p1_p2("Before p1.swap(p2): "); p1.swap(p2); print_p1_p2("After p1.swap(p2): "); swap(p1, p2); print_p1_p2("After swap(p1, p2): ");}
Output:
Before p1.swap(p2): p1 = {42, ABCD, 2.71}, p2 = {10, 1234, 3.14} After p1.swap(p2): p1 = {10, 1234, 3.14}, p2 = {42, ABCD, 2.71} After swap(p1, p2): p1 = {42, ABCD, 2.71}, p2 = {10, 1234, 3.14}
[edit]See also
swaps the contents of two tuple s (public member function) | |
(C++11) | specializes the std::swap algorithm (function template) |