std::make_unsigned
From cppreference.com
Defined in header <type_traits> | ||
template<class T > struct make_unsigned; | (since C++11) | |
If T
is an integral (except bool) or enumeration type, provides the member typedef type
which is the unsigned integer type corresponding to T
, with the same cv-qualifiers.
If T
is signed or unsigned char, short, int, long, longlong; the unsigned type from this list corresponding to T
is provided.
If T
is an enumeration type or char, wchar_t, char8_t(since C++20), char16_t, char32_t; the unsigned integer type with the smallest rank having the same sizeof
as T
is provided.
Otherwise, the behavior is undefined. | (until C++20) |
Otherwise, the program is ill-formed. | (since C++20) |
If the program adds specializations for std::make_unsigned
, the behavior is undefined.
Contents |
[edit]Member types
Name | Definition |
type | the unsigned integer type corresponding to T |
[edit]Helper types
template<class T > using make_unsigned_t =typename make_unsigned<T>::type; | (since C++14) | |
[edit]Example
Run this code
#include <type_traits> int main(){using uchar_type = std::make_unsigned_t<char>;using uint_type = std::make_unsigned_t<int>;using ulong_type = std::make_unsigned_t<volatilelong>; static_assert(std::is_same_v<uchar_type, unsignedchar> and std::is_same_v<uint_type, unsignedint> and std::is_same_v<ulong_type, volatileunsignedlong>);}
[edit]See also
(C++11) | checks if a type is a signed arithmetic type (class template) |
(C++11) | checks if a type is an unsigned arithmetic type (class template) |
(C++11) | obtains the corresponding signed type for the given integral type (class template) |