std::is_const
From cppreference.com
Defined in header <type_traits> | ||
template<class T > struct is_const; | (since C++11) | |
std::is_const
is a UnaryTypeTrait.
If T
is a const-qualified type (that is, const, or constvolatile), provides the member constant value equal to true. For any other type, value is false.
If the program adds specializations for std::is_const
or std::is_const_v
, the behavior is undefined.
Contents |
[edit]Template parameters
T | - | a type to check |
[edit]Helper variable template
template<class T > constexprbool is_const_v = is_const<T>::value; | (since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] | true if T is a const-qualified type, false otherwise (public static member constant) |
Member functions
operator bool | converts the object to bool, returns value (public member function) |
operator() (C++14) | returns value (public member function) |
Member types
Type | Definition |
value_type | bool |
type | std::integral_constant<bool, value> |
[edit]Notes
If T is a reference type then is_const<T>::value is always false. The proper way to check a potentially-reference type for constness is to remove the reference: is_const<typename remove_reference<T>::type>.
[edit]Possible implementation
template<class T>struct is_const :std::false_type{};template<class T>struct is_const<const T>:std::true_type{}; |
[edit]Example
Run this code
#include <type_traits> static_assert(std::is_same_v<constint*, intconst*>, "Remember, constness binds tightly inside pointers."); static_assert(!std::is_const_v<int>); static_assert(std::is_const_v<constint>); static_assert(!std::is_const_v<int*>); static_assert(std::is_const_v<int*const>, "Because the pointer itself can't be changed but the int pointed at can."); static_assert(!std::is_const_v<constint*>, "Because the pointer itself can be changed but not the int pointed at."); static_assert(!std::is_const_v<constint&>); static_assert(std::is_const_v<std::remove_reference_t<constint&>>); struct S {void foo()const{}void bar()const{}}; int main(){// A const member function is const in a different way: static_assert(!std::is_const_v<decltype(&S::foo)>, "Because &S::foo is a pointer."); using S_mem_fun_ptr =void(S::*)()const; S_mem_fun_ptr sfp =&S::foo; sfp =&S::bar;// OK, can be re-pointed static_assert(!std::is_const_v<decltype(sfp)>, "Because sfp is the same pointer type and thus can be re-pointed."); const S_mem_fun_ptr csfp =&S::foo;// csfp = &S::bar; // Error static_assert(std::is_const_v<decltype(csfp)>, "Because csfp cannot be re-pointed.");}
[edit]See also
(C++11) | checks if a type is volatile-qualified (class template) |
(C++17) | obtains a reference to const to its argument (function template) |