C++ named requirements:ValueSwappable(since C++11)
From cppreference.com
Two objects of this type can be dereferenced and the resulting values can be swapped using unqualified function call swap() in the context where both std::swap and the user-defined swap()s are visible.
[edit]Requirements
A type T is ValueSwappable if
T
satisfies the LegacyIterator requirements.- For any dereferenceable object
x
of typeT
(that is, any value other than the end iterator),*x
satisfies the Swappable requirements.
Many standard library functions expect their arguments to satisfy ValueSwappable, which means that any time the standard library performs a swap, it uses the equivalent of usingstd::swap; swap(*iter1, *iter2);.
[edit]Example
Run this code
#include <iostream>#include <vector> class IntVector {std::vector<int> v;// IntVector& operator=(IntVector); // not assignable (C++98 way)public: IntVector& operator=(IntVector)= delete;// not assignablevoid swap(IntVector& other){ v.swap(other.v);}}; void swap(IntVector& v1, IntVector& v2){ v1.swap(v2);} int main(){ IntVector v1, v2;// IntVector is Swappable, but not MoveAssignable IntVector* p1 =&v1; IntVector* p2 =&v2;// IntVector* is ValueSwappablestd::iter_swap(p1, p2);// OK: iter_swap requires ValueSwappable// std::swap(v1, v2); // compiler error! std::swap requires MoveAssignable}
[edit]See also
(C++20) | specifies that the values referenced by two indirectly_readable types can be swapped (concept) |