C++ named requirements:CopyConstructible
Specifies that an instance of the type can be copy-constructed from an lvalue expression.
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[edit]Requirements
The type T
satisfies CopyConstructible if
- The type
T
satisfies MoveConstructible, and
Given
- v, an lvalue expression of type
T
or const T or an rvalue expression of type const T, - u, an arbitrary identifier.
The following expressions must be valid and have their specified effects:
Expression | Post-conditions |
---|---|
T u = v; | The value of u is equivalent to the value of v. The value of v is unchanged. |
T(v) | The value of T(v) is equivalent to the value of v. The value of v is unchanged. |
The expression v.~T() also must be valid, and, for lvalue v, the expression &v must have the type | (until C++11) |
[edit]Notes
Until C++11, classes that overloaded operator& were not CopyConstructible and thus were not usable in the standard library containers. This is a design decision in C++98 (instead of a defect, see LWG issue 390).
Since C++11, the standard library uses std::addressof whenever the address of an object is needed.
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Being a CopyConstructible class implies std::is_copy_constructible but not vice versa since std::is_copy_constructible will only check for the ability to call the constructor with the correct arguments, and, e.g., not a MoveConstructible requirement. Run this code #include <type_traits>#include <utility> struct S { S()=default; S(S&&)= delete; S(const S&)=default;}; static_assert(std::is_copy_constructible_v<S>); int main(){ S s1; // Class `S` doesn't satisfy MoveConstructible requirement,// hence doesn't satisfy CopyConstructible requirement[[maybe_unused]] S s2{std::move(s1)};// ill-formed, use of deleted function} |
[edit]References
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[edit]See also
(C++11)(C++11)(C++11) | checks if a type has a copy constructor (class template) |
(C++20) | specifies that an object of a type can be copy constructed and move constructed (concept) |