std::prev
From cppreference.com
Defined in header <iterator> | ||
template<class BidirIt > BidirIt prev( BidirIt it, typenamestd::iterator_traits<BidirIt>::difference_type n =1); | (since C++11) (until C++17) | |
template<class BidirIt > constexpr | (since C++17) | |
Return the nth predecessor (or -nth successor if n is negative) of iterator it.
Contents |
[edit]Parameters
it | - | an iterator |
n | - | number of elements it should be descended |
Type requirements | ||
-BidirIt must meet the requirements of LegacyBidirectionalIterator. |
[edit]Return value
An iterator of type BidirIt
that holds the nth predecessor (or -nth successor if n is negative) of iterator it.
[edit]Complexity
Linear.
However, if BidirIt
additionally meets the requirements of LegacyRandomAccessIterator, complexity is constant.
[edit]Possible implementation
template<class BidirIt>constexpr// since C++17 BidirIt prev(BidirIt it, typenamestd::iterator_traits<BidirIt>::difference_type n =1){std::advance(it, -n);return it;} |
[edit]Notes
Although the expression --c.end() often compiles, it is not guaranteed to do so: c.end() is an rvalue expression, and there is no iterator requirement that specifies that decrement of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers or its operator-- is lvalue-ref-qualified, --c.end() does not compile, while std::prev(c.end()) does.
[edit]Example
Run this code
#include <iostream>#include <iterator>#include <vector> int main(){std::vector<int> v{3, 1, 4}; auto it = v.end();auto pv = std::prev(it, 2);std::cout<<*pv <<'\n'; it = v.begin(); pv = std::prev(it, -2);std::cout<<*pv <<'\n';}
Output:
1 4
[edit]See also
(C++11) | increment an iterator (function template) |
advances an iterator by given distance (function template) | |
returns the distance between two iterators (function template) | |
(C++20) | decrement an iterator by a given distance or to a bound (algorithm function object) |