std::unordered_map<Key,T,Hash,KeyEqual,Allocator>::begin, std::unordered_map<Key,T,Hash,KeyEqual,Allocator>::cbegin
来自cppreference.com
< cpp | container | unordered map
iterator begin()noexcept; | (1) | (C++11 起) (C++26 起为 constexpr) |
const_iterator begin()constnoexcept; | (2) | (C++11 起) (C++26 起为 constexpr) |
const_iterator cbegin()constnoexcept; | (3) | (C++11 起) (C++26 起为 constexpr) |
返回指向 *this 的首元素的迭代器。
如果 *this 为空,那么返回的迭代器等于 end()。
目录 |
[编辑]返回值
指向首元素的迭代器。
[编辑]复杂度
常数。
[编辑]示例
运行此代码
#include <cmath>#include <iostream>#include <unordered_map> struct Node {double x, y;}; int main(){ Node nodes[3]={{1, 0}, {2, 0}, {3, 0}}; // mag 是映射 Node 地址到其平面中长度的 mapstd::unordered_map<Node*, double> mag ={{ nodes +0, 1}, { nodes +1, 2}, { nodes +2, 3}}; // 从 0 到长度更改每个 y 坐标for(auto iter = mag.begin(); iter != mag.end();++iter){auto cur = iter->first;// 指向 Node 的指针 cur->y = mag[cur];// 亦能使用 cur->y = iter->second;} // 更新并打印每个结点的长度for(auto iter = mag.begin(); iter != mag.end();++iter){auto cur = iter->first; mag[cur]=std::hypot(cur->x, cur->y);std::cout<<"The magnitude of ("<< cur->x <<", "<< cur->y <<") is ";std::cout<< iter->second <<'\n';} // 以基于范围的 for 循环重复上述内容for(auto i : mag){auto cur = i.first; cur->y = i.second; mag[cur]=std::hypot(cur->x, cur->y);std::cout<<"The magnitude of ("<< cur->x <<", "<< cur->y <<") is ";std::cout<< mag[cur]<<'\n';// 注意与上述 std::cout << iter->second << '\n'; 相反,// std::cout << i.second << '\n'; 将不会打印更新的长度}}
可能的输出:
The magnitude of (3, 3) is 4.24264 The magnitude of (1, 1) is 1.41421 The magnitude of (2, 2) is 2.82843 The magnitude of (3, 4.24264) is 5.19615 The magnitude of (1, 1.41421) is 1.73205 The magnitude of (2, 2.82843) is 3.4641
[编辑]参阅
返回指向末尾的迭代器 (公开成员函数) | |
(C++11)(C++14) | 返回指向容器或数组起始的迭代器 (函数模板) |