std::vector<T,Allocator>::pop_back
From cppreference.com
void pop_back(); | (constexpr since C++20) | |
Removes the last element of the container.
If empty() is true, the behavior is undefined. | (until C++26) |
If empty() is true:
| (since C++26) |
Iterators and references to the last element are invalidated. The end()
iterator is also invalidated.
[edit]Complexity
Constant.
[edit]Example
Run this code
#include <vector>#include <iostream> namespace stq {template<typename T>void println(auto, const T& xz){std::cout<<'[';bool first{true};for(constauto& x : xz)std::cout<<(first ? first =false, "":", ")<< x;std::cout<<"]\n";}} int main(){std::vector<int> numbers{1, 2, 3}; stq::println("{}", numbers);while(not numbers.empty()){ numbers.pop_back(); stq::println("{}", numbers);}}
Output:
[1, 2, 3] [1, 2] [1] []
[edit]See also
adds an element to the end (public member function) |