std::erase, std::erase_if(std::vector)
From cppreference.com
Defined in header <vector> | ||
(1) | ||
template<class T, class Alloc, class U > constexprstd::vector<T, Alloc>::size_type | (since C++20) (until C++26) | |
template<class T, class Alloc, class U = T > constexprstd::vector<T, Alloc>::size_type | (since C++26) | |
template<class T, class Alloc, class Pred > constexprstd::vector<T, Alloc>::size_type | (2) | (since C++20) |
1) Erases all elements that compare equal to value from the container. Equivalent to
auto it = std::remove(c.begin(), c.end(), value);auto r = c.end()- it; c.erase(it, c.end());return r;
2) Erases all elements that satisfy the predicate pred from the container. Equivalent to
auto it =std::remove_if(c.begin(), c.end(), pred);auto r = c.end()- it; c.erase(it, c.end());return r;
Contents |
[edit]Parameters
c | - | container from which to erase |
value | - | value to be removed |
pred | - | unary predicate which returns true if the element should be erased. The expression pred(v) must be convertible to bool for every argument |
[edit]Return value
The number of erased elements.
[edit]Complexity
Linear.
Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_algorithm_default_value_type | 202403 | (C++26) | List-initialization for algorithm (1) |
[edit]Example
Run this code
#include <complex>#include <iostream>#include <numeric>#include <string_view>#include <vector> void println(std::string_view comment, constauto& c){std::cout<< comment <<'[';bool first{true};for(constauto& x : c)std::cout<<(first ? first =false, "":", ")<< x;std::cout<<"]\n";} int main(){std::vector<char> cnt(10);std::iota(cnt.begin(), cnt.end(), '0'); println("Initially, cnt = ", cnt); std::erase(cnt, '3'); println("After erase '3', cnt = ", cnt); auto erased = std::erase_if(cnt, [](char x){return(x -'0')%2==0;}); println("After erase all even numbers, cnt = ", cnt);std::cout<<"Erased even numbers: "<< erased <<'\n'; std::vector<std::complex<double>> nums{{2, 2}, {4, 2}, {4, 8}, {4, 2}};#ifdef __cpp_lib_algorithm_default_value_type std::erase(nums, {4, 2});#else std::erase(nums, std::complex<double>{4, 2});#endif println("After erase {4, 2}, nums = ", nums);}
Output:
Initially, cnt = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] After erase '3', cnt = [0, 1, 2, 4, 5, 6, 7, 8, 9] After erase all even numbers, cnt = [1, 5, 7, 9] Erased even numbers: 5 After erase {4, 2}, nums = [(2,2), (4,8)]
[edit]See also
removes elements satisfying specific criteria (function template) | |
(C++20)(C++20) | removes elements satisfying specific criteria (algorithm function object) |