How to run different python scripts from command line by passing the script name as argument

Question

I am using CentOs 6. I have got two scripts test1.py and test2.py in same directory.

I am running one test at a time as below from terminal:

py.test --html=report.html --self-contained-html test1.py

I want to create a shell script so that I can pass the script name (test1.py, test2.py) as parameter .

#!/bin/bash py.test --html=report.html --self-contained-html $testname — Sum, CommentedApr 15, 2018 at 15:30
The paramters you pass to the script can be access as $1, $2, etc. See mywiki.wooledge.org/BashGuide/Parameters — glenn jackman, CommentedApr 15, 2018 at 19:09

sinecode · Accepted Answer · 2018-04-15 22:36:29Z

Create a script run_test.sh as follow:

#!/bin/bash # Take the first argument with $1 py.test --html=report.html --self-contained-html $1

To run this script execute

$ bash run_test.sh <name_of_python_file>

Or make it executable with

$ chmod +x run_test.sh

and then you can launch it with

./run_test.sh <name_of_python_file>

1 Answer 1