let arr1 = [['item 1', 'item 2'],['item 3', 'item 4']] let arr2 = ['item 1', 'item 2'] I need to check whether arr2 exist in arr1
- You will have to use some and every. Does the order matter?– epascarelloCommentedMay 24, 2021 at 17:11
- This is a very popular gist that tackle this: jsfiddle.net/SamyBencherif/8352y6yw– Rodrigo RodriguesCommentedMay 24, 2021 at 17:26
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3 Answers
You can use Array#some along with Array#every.
let arr1 = [ ['item 1', 'item 2'], ['item 3', 'item 4'] ] let arr2 = ['item 1', 'item 2'] let res = arr1.some(x => x.length === arr2.length && x.every((e, i) => e === arr2[i])); console.log(res); answered May 24, 2021 at 17:15
- Thanks for the answer, now If I want to delete that item how can I?CommentedMay 24, 2021 at 17:38
- You can use
arr1.splice(arr1.findIndex(x => x.length === arr2.length && x.every((e, i) => e === arr2[i])), 1)CommentedMay 24, 2021 at 17:41
To keep it simple you can use the combination of every and some as below, it returns true if exists and false if not
arr1.some(i => i.length === arr2.length && i.every(it => arr2.includes(it))) 
- 1 . You can use findIndex and splice
let res = arr1.findIndex(x => x.length === arr2.length && x.every((e, i) => e === arr2[i])); arr1.splice(0,1); 2. you can directly use filterarr1 = arr1.filter(x => x.length !== arr2.length || x.some((e, i) => e !== arr2[i]));CommentedMay 25, 2021 at 4:51
If you want a very quick and easy way to check, you could do:
arr1.findIndex(arr => { return JSON.stringify(arr) === JSON.stringify(arr2) }) Which will return the position of arr2 within arr1, or '-1' if it does not exist in arr1
answered May 24, 2021 at 17:12
- Quick note: This will only work if you are trying to match the order (which you might be seeing as in JS arrays are ordered)CommentedMay 24, 2021 at 17:14
