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std::is_bind_expression

From cppreference.com
< cpp‎ | utility‎ | functional
 
 
 
Function objects
Partial function application
(C++20)(C++23)
(C++11)
is_bind_expression
(C++11)
Function invocation
(C++17)(C++23)
Identity function object
(C++20)
Old binders and adaptors
(until C++17*)
(until C++17*)
(until C++17*)
(until C++17*)  
(until C++17*)
(until C++17*)(until C++17*)(until C++17*)(until C++17*)
(until C++20*)
(until C++20*)
(until C++17*)(until C++17*)
(until C++17*)(until C++17*)

(until C++17*)
(until C++17*)(until C++17*)(until C++17*)(until C++17*)
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Defined in header <functional>
template<class T >
struct is_bind_expression;
(since C++11)

If T is a type produced by a call to std::bind (but not std::bind_front or std::bind_back), this template is derived from std::true_type. For any other type (unless user-specialized), this template is derived from std::false_type.

A program may specialize this template for a program-defined typeT to implement UnaryTypeTrait with base characteristic of std::true_type to indicate that T should be treated by std::bind as if it were the type of a bind subexpression: when a bind-generated function object is invoked, a bound argument of this type will be invoked as a function object and will be given all the unbound arguments passed to the bind-generated object.

Contents

[edit]Helper variable template

template<class T >
constexprbool is_bind_expression_v = is_bind_expression<T>::value;
(since C++17)

Inherited from std::integral_constant

Member constants

value
[static]
true if T is a function object generated by std::bind, false otherwise
(public static member constant)

Member functions

operator bool
converts the object to bool, returns value
(public member function)
operator()
(C++14)
returns value
(public member function)

Member types

Type Definition
value_typebool
typestd::integral_constant<bool, value>

[edit]Example

#include <functional>#include <iostream>#include <type_traits>   struct MyBind {typedefint result_type;int operator()(int a, int b)const{return a + b;}};   namespace std {template<>struct is_bind_expression<MyBind>:public true_type {};}   int f(int n1, int n2){return n1 + n2;}   int main(){// as if bind(f, bind(MyBind(), _1, _2), 2)auto b =std::bind(f, MyBind(), 2);   std::cout<<"Adding 2 to the sum of 10 and 11 gives "<< b(10, 11)<<'\n';}

Output:

Adding 2 to the sum of 10 and 11 gives 23

[edit]Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 2010C++11 program-defined specializations could
only be derived from std::false_type
can be derived from
std::true_type

[edit]See also

(C++11)
binds one or more arguments to a function object
(function template)[edit]
close