std::byte
Defined in header <cstddef> | ||
enumclass byte :unsignedchar{}; | (since C++17) | |
std::byte
is a distinct type that implements the concept of byte as specified in the C++ language definition.
Like unsignedchar, it can be used to access raw memory occupied by other objects (object representation), but unlike unsignedchar, it is not a character type and is not an arithmetic type. std::byte
models a mere collection of bits, supporting only bitshift operations with an integer, and bitwise and comparison operations with another std::byte
.
Contents |
[edit]Non-member functions
std::to_integer
template<class IntegerType > constexpr IntegerType to_integer( std::byte b )noexcept; | (since C++17) | |
Equivalent to: return IntegerType(b); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
std::operator<<=,operator>>=
template<class IntegerType > constexpr std::byte& operator<<=( std::byte& b, IntegerType shift )noexcept; | (1) | (since C++17) |
template<class IntegerType > constexpr std::byte& operator>>=( std::byte& b, IntegerType shift )noexcept; | (2) | (since C++17) |
This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
std::operator<<,operator>>
template<class IntegerType > constexpr std::byte operator<<( std::byte b, IntegerType shift )noexcept; | (1) | (since C++17) |
template<class IntegerType > constexpr std::byte operator>>( std::byte b, IntegerType shift )noexcept; | (2) | (since C++17) |
This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
std::operator|=,operator&=,operator^=
constexpr std::byte& operator|=( std::byte& l, std::byte r )noexcept; | (1) | (since C++17) |
constexpr std::byte& operator&=( std::byte& l, std::byte r )noexcept; | (2) | (since C++17) |
constexpr std::byte& operator^=( std::byte& l, std::byte r )noexcept; | (3) | (since C++17) |
std::operator|,operator&,operator^,operator~
constexpr std::byte operator|( std::byte l, std::byte r )noexcept; | (1) | (since C++17) |
constexpr std::byte operator&( std::byte l, std::byte r )noexcept; | (2) | (since C++17) |
constexpr std::byte operator^( std::byte l, std::byte r )noexcept; | (3) | (since C++17) |
constexpr std::byte operator~( std::byte b )noexcept; | (4) | (since C++17) |
[edit]Notes
A numeric value n can be converted to a byte value using std::byte{n}, due to C++17 relaxed enum class initialization rules.
A byte can be converted to a numeric value (such as to produce an integer hash of an object) the usual way with an explicit conversion or alternatively with std::to_integer
.
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_byte | 201603L | (C++17) | std::byte |
[edit]Example
#include <bitset>#include <cassert>#include <cstddef>#include <iostream>#include <utility> std::ostream& operator<<(std::ostream& os, std::byte b){return os <<std::bitset<8>(std::to_integer<int>(b));} int main(){// std::byte y = 1; // Error: cannot convert int to byte. std::byte y{1};// OK // if (y == 13) {} // Error: cannot be compared.if(y == std::byte{13}){}// OK, bytes are comparable int arr[]{1, 2, 3};// int c = a[y]; // Error: array subscript is not an integer[[maybe_unused]]int i = arr[std::to_integer<int>(y)];// OK[[maybe_unused]]int j = arr[std::to_underlying(y)];// OK auto to_int =[](std::byte b){return std::to_integer<int>(b);}; std::byte b{42};assert(to_int(b)==0b00101010);std::cout<< b <<'\n'; // b *= 2; // Error: b is not of arithmetic type b <<=1;assert(to_int(b)==0b01010100); b >>=1;assert(to_int(b)==0b00101010); assert(to_int(b <<1)==0b01010100);assert(to_int(b >>1)==0b00010101); b |= std::byte{0b11110000};assert(to_int(b)==0b11111010); b &= std::byte{0b11110000};assert(to_int(b)==0b11110000); b ^= std::byte{0b11111111};assert(to_int(b)==0b00001111);}
Output:
00101010