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std::byte

From cppreference.com
< cpp‎ | types
 
 
 
 
Defined in header <cstddef>
enumclass byte :unsignedchar{};
(since C++17)

std::byte is a distinct type that implements the concept of byte as specified in the C++ language definition.

Like unsignedchar, it can be used to access raw memory occupied by other objects (object representation), but unlike unsignedchar, it is not a character type and is not an arithmetic type. std::byte models a mere collection of bits, supporting only bitshift operations with an integer, and bitwise and comparison operations with another std::byte.

Contents

[edit]Non-member functions

std::to_integer

template<class IntegerType >
constexpr IntegerType to_integer( std::byte b )noexcept;
(since C++17)

Equivalent to: return IntegerType(b); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.

std::operator<<=,operator>>=

template<class IntegerType >
constexpr std::byte& operator<<=( std::byte& b, IntegerType shift )noexcept;
(1) (since C++17)
template<class IntegerType >
constexpr std::byte& operator>>=( std::byte& b, IntegerType shift )noexcept;
(2) (since C++17)
1) Equivalent to: return b = b << shift; This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
2) Equivalent to: return b = b >> shift;

This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.

std::operator<<,operator>>

template<class IntegerType >
constexpr std::byte operator<<( std::byte b, IntegerType shift )noexcept;
(1) (since C++17)
template<class IntegerType >
constexpr std::byte operator>>( std::byte b, IntegerType shift )noexcept;
(2) (since C++17)
1) Equivalent to: return std::byte(static_cast<unsignedint>(b)<< shift); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
2) Equivalent to: return std::byte(static_cast<unsignedint>(b)>> shift);

This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.

std::operator|=,operator&=,operator^=

constexpr std::byte& operator|=( std::byte& l, std::byte r )noexcept;
(1) (since C++17)
constexpr std::byte& operator&=( std::byte& l, std::byte r )noexcept;
(2) (since C++17)
constexpr std::byte& operator^=( std::byte& l, std::byte r )noexcept;
(3) (since C++17)
1) Equivalent to: return l = l | r;.
2) Equivalent to: return l = l & r;.
3) Equivalent to: return l = l ^ r;.

std::operator|,operator&,operator^,operator~

constexpr std::byte operator|( std::byte l, std::byte r )noexcept;
(1) (since C++17)
constexpr std::byte operator&( std::byte l, std::byte r )noexcept;
(2) (since C++17)
constexpr std::byte operator^( std::byte l, std::byte r )noexcept;
(3) (since C++17)
constexpr std::byte operator~( std::byte b )noexcept;
(4) (since C++17)
1) Equivalent to: return std::byte(static_cast<unsignedint>(l)|static_cast<unsignedint>(r));.
2) Equivalent to: return std::byte(static_cast<unsignedint>(l)&static_cast<unsignedint>(r));.
3) Equivalent to: return std::byte(static_cast<unsignedint>(l)^static_cast<unsignedint>(r));.
4) Equivalent to: return std::byte(~static_cast<unsignedint>(b));

[edit]Notes

A numeric value n can be converted to a byte value using std::byte{n}, due to C++17 relaxed enum class initialization rules.

A byte can be converted to a numeric value (such as to produce an integer hash of an object) the usual way with an explicit conversion or alternatively with std::to_integer.

Feature-test macroValueStdFeature
__cpp_lib_byte201603L(C++17)std::byte

[edit]Example

#include <bitset>#include <cassert>#include <cstddef>#include <iostream>#include <utility>   std::ostream& operator<<(std::ostream& os, std::byte b){return os <<std::bitset<8>(std::to_integer<int>(b));}   int main(){// std::byte y = 1; // Error: cannot convert int to byte. std::byte y{1};// OK   // if (y == 13) {} // Error: cannot be compared.if(y == std::byte{13}){}// OK, bytes are comparable   int arr[]{1, 2, 3};// int c = a[y]; // Error: array subscript is not an integer[[maybe_unused]]int i = arr[std::to_integer<int>(y)];// OK[[maybe_unused]]int j = arr[std::to_underlying(y)];// OK   auto to_int =[](std::byte b){return std::to_integer<int>(b);};   std::byte b{42};assert(to_int(b)==0b00101010);std::cout<< b <<'\n';   // b *= 2; // Error: b is not of arithmetic type b <<=1;assert(to_int(b)==0b01010100);   b >>=1;assert(to_int(b)==0b00101010);   assert(to_int(b <<1)==0b01010100);assert(to_int(b >>1)==0b00010101);   b |= std::byte{0b11110000};assert(to_int(b)==0b11111010);   b &= std::byte{0b11110000};assert(to_int(b)==0b11110000);   b ^= std::byte{0b11111111};assert(to_int(b)==0b00001111);}

Output:

00101010
close