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std::inplace_vector<T,N>::pop_back

From cppreference.com
 
 
 
 
constexprvoid pop_back();

Removes the last element of the container.

If empty() is true:

  • If the implementation is hardened, a contract violation occurs. Moreover, if the contract-violation handler returns under “observe” evaluation semantic, the behavior is undefined.
  • If the implementation is not hardened, the behavior is undefined.

Iterators and references to the last element are invalidated. The end() iterator is also invalidated.

[edit]Complexity

Constant.

[edit]Example

#include <inplace_vector>#include <print>   int main(){std::inplace_vector<int, 4> numbers{1, 2, 3};for(; not numbers.empty(); numbers.pop_back())std::println("{}", numbers);}

Output:

[1, 2, 3] [1, 2] [1]

[edit]See also

adds an element to the end
(public member function)[edit]
close