std::common_type<std::chrono::duration>
From cppreference.com
Defined in header <chrono> | ||
template<class Rep1, class Period1, class Rep2, class Period2 > struct common_type<std::chrono::duration<Rep1, Period1>, | (since C++11) | |
Exposes the type named type
, which is the common type of two std::chrono::durations, whose period is the greatest common divisor of Period1
and Period2
.
Contents |
[edit]Member types
Member type | Definition |
type | std::chrono::duration<typenamestd::common_type<Rep1, Rep2>::type, /* see note */> |
[edit]Note
The period of the resulting duration can be computed by forming a ratio of the greatest common divisor of Period1::num and Period2::num and the least common multiple of Period1::den and Period2::den.
[edit]Example
Run this code
#include <chrono>#include <iostream>#include <type_traits> // std::chrono already finds the greatest common divisor,// likely using std::common_type<>. We make the type// deduction externally. template<typename T,typename S>constexprauto durationDiff(const T& t, const S& s)->typenamestd::common_type<T,S>::type{typedeftypenamestd::common_type<T,S>::type Common;return Common(t)- Common(s);} int main(){usingnamespace std::literals; constexprauto ms = 30ms;constexprauto us = 1100us;constexprauto diff = durationDiff(ms, us); std::cout<< ms <<" - "<< us <<" = "<< diff <<'\n';}
Output:
30ms - 1100us = 28900us
[edit]See also
specializes the std::common_type trait (class template specialization) | |
(C++11) | determines the common type of a group of types (class template) |