Python Web-Scraping with BeautifulSoup

Question

I'm relatively new to python and for an assignment I had to write a program that fetches a webpage with BeautifulSoup, extract all Paragraphs from it, and extract all words ending with "ing", and in the end save it to a file with the format "Word" + tab + "wordcount" + "newline".

This is my code so far. Is there a more pythonic way to handle this? Or generally ways to improve the code?

from bs4 import BeautifulSoup import requests import re def main(): site = "https://en.wikipedia.org/wiki/Data_science" r = requests.get(site).content soup = BeautifulSoup(r) ps = soup.findAll('p') fulltext = '' for p in ps: fulltext += p.get_text() words = match_words(fulltext) formated_words = sort_and_format(words) with open(r"Q1_Part1.txt","w") as file: file.write(formated_words) def match_words(string): pattern = re.compile(r'\b(\w*ing)\b') words = re.findall(pattern, string.lower()) matching_words = {} for word in words: if word in matching_words: matching_words[word] += 1 else: matching_words[word] = 1 return matching_words def sort_and_format(dict): ordered_keys = sorted(dict, key=dict.get, reverse=True) output_string = '' for r in ordered_keys: output_string += f"{r}\t{dict[r]}\n" return output_string main() 

Answer 1

if word in matching_words: matching_words[word] += 1 else: matching_words[word] = 1 

If you're checking if a dictionary has a key before adding to it, a defaultdict may be a better option:

from collections import defaultdict matching_words = defaultdict(int) matching_words[word] += 1 

int returns a 0 when called without arguments, and that 0 is used as a default value for the dictionary when the key doesn't exist.

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fulltext = '' for p in ps: fulltext += p.get_text() 

This isn't very efficient. Performance of += on strings has gotten better in later versions of Python, but it's still generally slower. The typical alternative is using join:

pieces = [p.get_text() for p in ps] fulltext = "".join(pieces) # Or just fulltext = "".join([p.get_text() for p in ps]) 

Then similarly in sort_and_format:

output_string = "".join([f"{r}\t{dict[r]}\n"] for r in ordered_keys]) 

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In sort_and_format, you've named the parameter dict. This is suboptimal for a couple reasons:

• dict is a generic name that doesn't properly describe the data.
• dict is the name of a built-in class, and shadowing it makes your code more confusing, and prevents you from using the built-in.

Indicating the type can be helpful though, so I might introduce type hints here

from typing import Dict def sort_and_format(words: Dict[str, int]) -> str: . . . 

This says that the functions accepts a Dictionary mapping strings to ints, and returns a string

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Also for sort_and_format, I've found that when you start sticking and into names, that can suggest that the function is doing too much. You may find that the code will make more sense if the sorting and formatting happen separately. That functions can handle purely formatting, and can be handed a sequence to work with instead. If that sequence is sorted, great, if not, also great. It doesn't matter for the purposes of formatting what the sort order is.