Challenge
https://leetcode.com/explore/interview/card/top-interview-questions-easy/93/linked-list/773/
Given a linked list, determine if it has a cycle in it.
To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is no cycle in the linked list.
Example 1:
Input: head = [3,2,0,-4], pos = 1 Output: true Explanation: There is a cycle in the linked list, where tail connects to the second node.
Example 2:
Input: head = [1,2], pos = 0 Output: true Explanation: There is a cycle in the linked list, where tail connects to the first node.
Example 3:
Input: head = [1], pos = -1 Output: false Explanation: There is no cycle in the linked list.
Follow up
- Can you solve it using \$O(1)\$ (i.e. constant) memory?
- Can you please review about performance?
using System; using Microsoft.VisualStudio.TestTools.UnitTesting; namespace LinkedListQuestions { public class ListNode { public int val; public ListNode next; public ListNode(int x) { val = x; } } [TestClass] public class HasCycleTest { [TestMethod] public void HasCycle() { ListNode head = new ListNode(3); head.next = new ListNode(2); head.next.next = new ListNode(0); head.next.next.next = new ListNode(-4); head.next.next.next.next = head.next; //2 Assert.IsTrue(HasCycleClass.HasCycle(head)); } [TestMethod] public void NoCycle() { ListNode head = new ListNode(3); head.next = new ListNode(2); head.next.next = new ListNode(0); Assert.IsFalse(HasCycleClass.HasCycle(head)); } [TestMethod] public void OneItem() { ListNode head = new ListNode(3); Assert.IsFalse(HasCycleClass.HasCycle(head)); } } public class HasCycleClass { public static bool HasCycle(ListNode head) { if (head == null || head.next == null) { return false; } ListNode slow = head.next; ListNode fast = head.next.next; while(fast!= null) { if (fast == slow) { return true; } else { slow = slow.next; if (fast.next == null) { return false; } fast = fast.next.next; } } return false; } } }