Member Avatar for dss1984

Hi, everyone. This is my first post here. I'm not very good with C++ and I have to write a program using 2 dimensional arrays.

My program is a Menu that works with 2 two dimensional arrays. The program has to generate two random matrices and perform arthimetic procedures like addition and subtraction. My program generates the matrices perfectly, but I'm having a lot of trouble writing the function to add the two matrices. I know that in order to add to matrices you have to sum the elements in every row and column and store them into a new matrix, but I can't figure out how to write the actual code for it. Can anyone help? PLEASE! Here is the code I have written so far for the program. The addition part of the code is being written in the last function.

//February 7, 2005 #include <iostream> #include <cstdlib> #include <ctime> #include <iomanip> using namespace std; const int ROW = 3; //global constant for row const int COL = 3; //global constant for column const int LOW = 1; //global const for lower limit const int UP = 10; //global const for upper limit void RandomArray(int[][COL],int, int, int, int); //Random array generator function prototype void Menu(); //Menu function prototype void PrintArray(int[][COL],int,int); //Print array function prototype void AddArray(int[][COL],int[][COL],int,int); int main() { srand(time(NULL)); int matrix[ROW][COL]; //Array declaration int NewMatrix[ROW][COL]; int menuOption; RandomArray(matrix, ROW, COL, LOW, UP); //Function call do { Menu(); cin >> menuOption; cout << endl; switch(menuOption) { case 1: RandomArray(matrix, ROW, COL, LOW, UP); PrintArray(matrix,ROW,COL); RandomArray(matrix, ROW, COL, LOW, UP); PrintArray(matrix,ROW,COL); AddArray(matrix,NewMatrix,ROW,COL); PrintArray(matrix,ROW,COL); break; case 7: PrintArray(matrix,ROW,COL); RandomArray(matrix, ROW, COL, LOW, UP); PrintArray(matrix,ROW,COL); break; default: cout << "Invalid Option." << endl; break; } }while (menuOption != 0); return 0; } void Menu() { cout << endl << "Menu Options: " << endl << endl << "1. Add 2 matrices " << endl << "2. Subtract 2 matrices " << endl << "3. Multiply 2 matrices " << endl << "4. Multiply matrix by a constant " << endl << "5. Transpose matrix " << endl << "6. Matrix trace " << endl << "7. Print " << endl << "0. EXIT " << endl; } void RandomArray(int table[ ][COL], int row, int col, int lowerLimit, int upperLimit) { for (int r = 0; r < ROW; r++) for (int c = 0; c < COL; c++) table[r][c] = rand()%(upperLimit - lowerLimit + 1) + lowerLimit; } void PrintArray(int table[][COL], int row, int col) { for (row = 0; row < ROW; row++) { for (col = 0; col < COL; col++) cout << setw(3) << table[row][col]; cout << endl; } cout << endl; } void AddArrays(int table[][COL], int theMatrix[][COL], int row, int col) { for (int r=0; r < row; r++) for (int c=0; c < col; c++) theMatrix[r][c]= table[r][c]+ table[r][c]; }

By the way, should my AddArray function be a value-returning function?

Member Avatar for dss1984

Nevermind. I just figured it out.

Member Avatar for CloudyBoy

thanks,,, its useful 4 me

Member Avatar for ameya potnis
#include<stdio.h> #include<conio.h> void main() { int a[10][10],b[10][10],d[10][10],i,j,r,c; clrscr(); printf("enter the value for ROWS:"); scanf("%d",&r); printf("enter the value of COLUMNS:"); scanf("%d",c); for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("enter the element:"); scanf("%",&a[i][j]); } } for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("\t %d",a[i][j]); } { printf("\n"); } } for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("enter the element:"); scanf("%",&b[i][j]); } } for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("\t %d",b[i][j]); } { printf("\n"); } } printf("answer of a+b:\n"); for(i=0;i<r;i++) { for(j=0;j<c;j++) { d[i][j]=a[i][j]+b[i][j]; } } for(i=0;i<r;i++) { for(j=0;j<c;j++) { printf("\t %d",d[i][j]); } { printf("\n"); } } getch(); } 

this programe is done to get two nos. from the user and print the entered no. into rows and columns and acccordingly add both the matrix.....

commented: Not even in C++, non-standard, no code tags, no dice-1
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