bash scripting key value array in "etc/passwd" file

Question

I want my /etc/passwd file to be as an array like this

[user_id] => [home_directory]

e.g.

[0] => "/root" [1000] => "/home/user1" [1001] => "/home/user2" 

so after that, I can set a condition that if user_id is greater than 999 (it mean usual users) then check if in .htaccess file of its directory the values of memory_limit and display_errors are exists or not.

for the aforesaid goal, I ran the command bellow

cat /etc/passwd | awk -F':' '{print $4,$6}'

it shows all

user_id home_directory

but I don't know how to put them in the array I mentioned before.

because some users in /etc/passwd have no home directory my array keys get incorrect values.

please help.

thanks in advance.

Answer 1

You can use a shell array

# Associative array p declare -A p=() # Populate the array (x is a placeholder that we otherwise ignore) while IFS=: read -r x x uid x x home x do p[$uid]=$home done </etc/passwd # Demonstrate the data for uid in "${!p[@]}" do printf "[%s]\t=> \"%s\"\n" "$uid" "${p[$uid]}" done 

Example output

[1000] => "/home/pi" [0] => "/root" [1] => "/usr/sbin" [33] => "/var/www" 

Answer 2

Try this

IFS=$'\n' user=( $(awk -F':' '{print $4}' /etc/passwd | tr '\n' ' ') ) homeDir=( $(awk -F':' '{print $6}' /etc/passwd |tr '\n' ' ')) unset IFS