bash script select menu

Question

I've many notes gleaned from the web and have written bash scripts to manage them.

I've some scripts working that depend on select to make menus.

Question: in a nested menu context, is it possible to revert to a preceding menu within the script ? I've a strong feeling that this may not be possible but am posting this in the hope there may be a way.

To explain what I mean: say the user makes a choice against menu-1 which then determines what shows up in menu-2 which follows. If the user selects "done" in menu-2, is there a loop device to bring the user back to menu-1 ?

The script below contains 3 selects - I'd like to be able to revert from the 3rd one back to the 2nd:

curd=($(ls)); # array select dirup in ${curd[@]} done do cd $dirup; ar=($(ls | awk -F"." '{ print $1 }' | awk -F"-" '{ for(i=2; i<=NF; i++) print $i }' | sort | uniq)); select choice in ${ar[@]} done # select list do echo "you selected: $choice" [[ $choice == "done" ]] && exit ar=($( find . -type f -maxdepth 1 -name "*$choice*" )); ((cnt=${#ar[@]}+1)) select ntit in ${ar[@]} done do echo "choice is:[ $REPLY ]" for i in $REPLY; # $REPLAY contains numbers do if [ $i -lt $cnt ] then ((var=$i-1)); open ${ar[$var]}; else exit fi done done done done 

Answer 1

Use break instead of exit. Note, though, that the menu is not reprinted when returning to a higher menu.

Example:

select x in nothing inner quit ; do [[ $x == quit ]] && break if [[ $x == inner ]] ; then select y in NOTHING BACK ; do [[ $y == BACK ]] && break done fi done