Reading variable from another file into bash

Question

I have written a bash script which calls other process (the ones that ask for password on terminal).

#!/bin/bash source pc.txt snp_pw=$export_snapshot export snapshot_pw=snp_pw echo_time() { date "+%d:%b:%Y:%H:%M:%S" } # Export Snapshot echo "$(echo_time) :STARTING EXPORT SNAPPSHOT SCRIPT" | tee -a ${mail_log} loop_var=3 echo "$(echo_time) :ON FAILURE TRY AT MAX ${loop_var} ATTEMPTS" | tee -a ${mail_log} i=1 while [ "${loop_var}" -gt 0 ]; do expect <(cat << 'EOD' spawn $::env(Snp_Script_Path)/export_service_instance.sh bootstrap Export_Files/test.bar expect "Enter RPD Password:" send -- "$::env(snapshot_pw)\r" expect "Re-enter RPD Password:" send -- "$::env(snapshot_pw)\r" interact EOD ) &> ${export_snapshot_log_location} 

Instead of directly hardcoding the password here, how can I read it from within a variable in other file?

It has to be a bash and expect both. I am currently trying to read the file through source and $pass gives password. But within expect, it is not working.

I don't want to encrypt/encode anything. I just want to keep it simple.

Answer 1

I'm not sure of everything that's happening, and what is supposed to be happening, but when you say

export snapshot_pw=snp_pw 

you are setting the environment variable snapshot_pw to the string s n p _ p w.  You probably want to do

export snapshot_pw="$snp_pw" 

to set the environment variable snapshot_pw to the value of variable snp_pw, i.e., $snp_pw.

Also, you should quote the shell variable "$mail_log" and any others you use without quoting.  (You don't need the { and }.)

Answer 2

A minimal test case shows that both bash and expect do read the same environment variable:

#!/bin/bash export foo="bar$$" echo "bash $foo" expect <(cat <<'EOD' puts "tcl $env(foo)" EOD ) 

which when run shows the same values in both languages:

-bash-4.2$ bash mixin bash bar7242 tcl bar7242 -bash-4.2$ bash mixin bash bar7247 tcl bar7247 -bash-4.2$ 

so it is not clear what you mean by "it is not reading" nor what your overall goal is for this code.

Answer 3

You can set a variable based on the contents of a file with a syntax like

snp_pw="$(cat passwd_file)" 

e.g.

$ cat passwd_file anewpassword $ cat x #!/bin/bash snp_pw=$(cat passwd_file) echo Password is $snp_pw $ ./x Password is anewpassword