Print output matching pattern till other pattern match

Question

I am trying to print text after a pattern match till it matches other pattern several times in a file. I have tried to modify the script given here but failed to do it. eg. The content of file1.txt

example text more example pattern1 important text very important need this too pattern2 i dont require this junk text more junk pattern1 important text very important need this too pattern2 junk 

Expected Output

pattern1 important text very important need this too pattern1 important text very important need this too 

can anyone suggest the edit?

Thanks.

Answer 1

Matching between lines between patterns, including either boundary, is a standard range selector in sed:

sed -n -e '/pattern1/,/pattern2/p' example.txt 

Depending on how efficiency-critical you are (how big the files are), I'd probably be lazy and use a second pass to delete the pattern2 markers:

cat example.txt \ | sed -n -e '/pattern1/,/pattern2/p' \ | sed -e '/pattern2/d' 

(Yes, this is a useless use of cat, because I prefer the readability of chaining several piping filters over the performance loss, and I'm not sure right now if < example.txt | sed ... | sed ... is mandated by POSIX or just an extension that happens to be present in bash and zsh.)