Syntax error: "integer expression expected"

Question

I am using below script

x=5.44 p=0 temp=$(printf "%.*f\n" $p $x) echo $temp if [ temp -gt 0 ] then echo "inside" fi 

and I am getting below output with error.

5 ./temp.sh: line 6: [: temp: integer expression expected 

Answer 1

You need to use $ for the shell to expand temp (As your script is written you are trying to compare the literal string temp to the integer 0). You also should quote it:

x=5.44 p=0 temp=$(printf "%.*f\n" $p $x) echo "$temp" if [ "$temp" -gt 0 ] then echo "inside" fi 

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If you are using bash a better way to do it would be using bash arithmetic expression like so:

x=5.44 p=0 temp=$(printf "%.*f\n" $p $x) echo "$temp" if ((temp>0)); then echo "inside" fi 

Inside of the arithmetic expression ((…)) you do not need a $ for expansion and you cannot quote.