Bash script inheritance? Calling a function from another script?

Question

I have this line:

trap 'jobs -p | xargs kill -9' SIGINT SIGTERM EXIT

it is repeated in many bash shell scripts I have.

What is the best way to share this code? Can I call a bash function perhaps?

In reality, I am creating a framework and the user will be expected to write some glue shell scripts. What would be nice if the user's shell scripts could inherit from a base shell script, somehow. Or they could just call bash functions that pre-exist somehow.

The problem is that if I create a bash function like so:

// a.sh function trap_and_kill_child_jobs { trap 'jobs -p | xargs kill -9' SIGINT SIGTERM EXIT } 

and call it from another script like so:

// b.sh source ./a.sh trap_and_kill_child_jobs sh -c 'sleep 10000 &' & # I want this process to be killed by `trap_and_kill_child_jobs` ./run-some-tests.js 

the caller script (b.sh) does not actually experience the trap. The 'child jobs' created by b.sh will continue running.

Answer 1

It would be enough create a script file that contain your framework functions like this:

/tmp/framework.sh

# Define a serie of functions of your framework... function framework_function_1() { echo "function 1 executed" } function framework_function_2() { echo "function 2 executed" } # And put here anything you want to be executed right away (like the trap) echo "framework.sh was executed" 

Then include it in the rest of your scripts like this:

/tmp/b.sh

# Include the framework: . /tmp/framework.sh echo "Script b.sh was executed" # Calling a framework's function framework_function_2 

With this the execution of b.sh (and any other script including framework.sh) will be like:

$ /tmp/b.sh framework.sh was executed Script b.sh was executed function 2 executed 

Note that . /tmp/framework.sh is the same as source /tmp/framework.sh.