Matching word inside multiple strings

Question

Below code is working fine:

#!/bin/bash str='fail' var1='pass' var2='ok' var3='fail' var4='pass' case $str in $var1|$var2|$var3|$var4) echo yes ;; *) echo no ;; esac 

When I execute this, as expected I get output yes.

In above code, value of variables are not hard-coded, these are coming from previous run, so it keep changing. Here the problem is, sometime it comes like:

var3='partial|fail' 

Any variable value can change like this. So in this case it gives no. What should I do change in my code so it handle this situation and match fail word and show the result yes?

Answer 1

Do the case on str,

case $var1$var2$var3$var4 in *$str*) echo yes ;; *) echo no ;; esac 

Answer 2

 case $var1 in *"$str"* ) echo yes ;; * ) case $var2 in *"$str"* ) echo yes ;; * ) case $var3 in *"$str"* ) echo yes ;; * ) case $var4 in *"$str"* ) echo yes ;; * ) echo no ;; esac;; esac;; esac;; esac 

With your approach we will have to resort to eval.

Another method:

unset -v f A=( "$var1" "$var2" "$var3" "$var4" ) for var in "${A[@]}"; do case $var in *"$str"* ) f=; echo yes; break;; esac; done ${f+:} echo no 

Answer 3

#!/bin/bash str="fail"; echo ${str} |awk -v var1="pass" \ -v var2="ok" \ -v var3="partial|fail" \ -v var4="pass" \ '{ if (( $0 ~ var1 ) || ( $0 ~ var2 ) || ( $0 ~ var3 ) || ( $0 ~ var4 )) { print "yes"; } else { print "no"; }}' 

You can replace quoted var assignments above with on-the-fly values as needed. If I've understood requirement, it is that "yes" be output whenever "str" is matched to some part of one of the vars?