For an script I'm making I need to convert the output of a command to an array. For simplifying I have made an example using echo:
arr=( $(echo '"test example" "test2 example"') ) What I want is the first element of the array to be
test example but when doing this:
echo ${arr[0]} I get
"test What I have to do to get the result I want?
Suppose echo do not produce right output like a command so have to include sed
mapfile -t arr < <( echo '"test example1" "test2 example2"' | sed 's/" "/"\n"/g' ) 
eval "arr=( $(echo '"test example" "test2 example"') )" echo "${arr[0]}" for e in "${arr[@]}"; do echo "<$e>" done test example <test example> <test2 example> eval is the easy way here, but just note that it runs the whole input as a shell command, doing much more than interpreting the quotes. Variables in the quoted strings will be expanded, so if the output contains $ it may get corrupted. Also, anything outside quotes will be taken as shell syntax, e.g. an unquoted ) will break the array assignment syntax. Also, if someone actively wants to ruin your day, command expansions will be an easy way to do that.
echothere. What you can do isarr=("test example" "test2 example"); echo "${arr[0]}". This is how you create an simple array in bash.evalmethod suggested in an answer is dangerous since the output of the command will be evaluated — whatever controls the output of that command can cause your script to run whatever program they want) and the definition is ambiguous (e.g. can you have a"in an element? how? What do you do if the output doesn't contain balanced quotes? …)."word word" "word word"(...) It outputs two words with a space in the middle of them surrounded by quotes and each one of these separated by spaces. If there are quotes they are escaped\". The eval as you and @ilkkachu said has risks. I might look into either changing the program I execute if I can or making my own replacement so the output can be more easily used, maybe using mapfile.