Bash function with arguments

Question

I know I can write bash scripts like:

foo() { echo $1; } 

but can I define a function that writes:

foo(string) { echo $string; } 

I just can't find my way out of this.

Answer 1

The only available form is the first one; see the manual for details.

To use named parameters, the traditional technique is to assign them at the start of your function:

foo() { string=$1 # ... echo "${string}" }