Read Input From Command Line

Question

Trying to use the "read command" to accept user input from the command prompt itself but my script doesnt seem to be moving forward

echo "Do you want to continue?(yes/no)" read -p $1 if [ "$1" == "yes" ] then sleep 5s echo "" echo " move ahead" else echo "" echo "Skipping The Step.." echo "" sleep 5s fi 

I want to execute the script like this..

sh script.sh yes sh script.sh no 

Added a -p to the above script and all seems to work very well. This is my real problem. I have another script test.sh which calls script.sh. So this is how i put the input

cat test.sh yes #!/bin/bash echo "execute the below script" sh script.sh $1 sh test.sh yes 

This way doesnt work as the script picks up a default no and moves ahead. Any ideas.

Answer 1

$1,$2 … - command line positional arguments and couldn't be assigned like read [-p] $1 or any other way except

set -- firsr_arg second_arg … 

For your case it can be test if arguments is present then test them

while [ -z "$REPLY" ] ; do if [ -z "$1" ] ; then read -p "Do you want to continue?(yes/no) " else REPLY=$1 set -- fi case $REPLY in [Yy]es) sleep 5s echo -e "\n move ahead" ;; [Nn]o) echo -e "\nSkipping The Step..\n" sleep 5s ;; *) echo "Wrong answer. Print 'yes' or 'no'" unset REPLY ;; esac done