reformatting command output within bash script

Question

within script the attempt here is to remove the : and then revert the / to \ within the print out

currently I have to display the linux path: The home directory is located here: rtp1-filer-ns:/homedir-private/private007/user

and would like to reformat as for my users ease Windows path to home directory: \rtp1-filer-ns\homedir-private\private007\user

currently this part of the script is as follows

 echo "The shell is: `ypmatch $EndUser passwd | awk -F\: '{ print $7 }'`" echo "" echo "The home directory is located here:" ypmatch $EndUser auto_home echo "" echo "Windows path to home directory:" echo "\\\\`ypmatch $EndUser auto_home | awk -F':' '{print $1}'`\\$EndUser" 

gives me the print out of :

 The home directory is located here: rtp1-filer-ns:/homedir-private/private007/user Windows path to home directory: \\rtp1-filer-ns\user 

assuming i can use sed /awk something of the sorts , open for suggestions $EndUser is a defined var

Answer 1

With bash

First approach - use parameter substitution

#use command substitution to set command output into variable var var=$(ypmatch $EndUser auto_home) #strip out the first : var=${var/:} #replace all instances of / with \ var=${var//\//\\} echo $var rtp1-filer-ns\homedir-private\private007\user 

Second approach - use arrays

# Set path components into array frags IFS=/ read -a frags < <(ypmatch $EndUser auto_home) # Strip ":" off rtp1-filer-ns frags[0]="${frags[0]%:}" # Set IFS to \ to print frags \-separated echo "$(IFS=\\ ;printf '%s\n' "${frags[*]}";)" rtp1-filer-ns\homedir-private\private007\user