Sort array of object by another array of object

Question

I have two arrays of objects with the same length.

one= [ { id: 3, name: 'a'}, { id: 5, name: 'b'}, { id: 4, name: 'c'} ]; two= [ { id: 7, name: 'b'}, { id: 6, name: 'c'}, { id: 2, name: 'a'} ]; 

I want to sort array 'two' by name property that depends on array 'one'.

My solution is

const tempArray = []; one.forEach((x) => { tempArray.push(two.find(item => item.name === x.name)); 

But is there a way to do this without creating tempArray?

I mean a one line solution?

Answer 1

You could use map function:

const tempArray = one.map(x => two.find(item => item.name === x.name)); 

Alternatively, if you are not striving for brevity:

const nameToPosMap = Object.fromEntries(one.map((x, idx) => [x.name, idx])); two.sort((i1, i2) => nameToPosMap[i1.name] - nameToPosMap[i2.name]) 

This may be faster as it avoids repeated find calls.