How to sort an array of Objects using string type object's key values

Question

I have an array like this

 let years =[ {id: 3, name: "2016", age: "None"}, {id: 1, name: "2017", age: "None"}, {id: 2, name: "2015", age: "None"}, {id: 5, name: "2018", age: "None"}, {id: 3, name: "2018/2019", age: "None"} ] years.sort((c1, c2) => { return c2.name - c1.name; }); console.log(years); 

I couldn't deal with this "2018/2017" way how can I do it what is the best way to do it

Answer 1

You can use localeCompare

const years = [ { id: 3, name: '2016', age: 'None' }, { id: 1, name: '2017', age: 'None' }, { id: 2, name: '2015', age: 'None' }, { id: 5, name: '2018', age: 'None' }, { id: 3, name: '2018/2019', age: 'None' }, ]; years.sort((c1, c2) => c2.name.localeCompare(c1.name)); console.log(years);

Answer 2

You are almost there...Just a little change in your sort callback and it's done::

let years = [ { id: 3, name: '2016', age: 'None' }, { id: 1, name: '2017', age: 'None' }, { id: 2, name: '2015', age: 'None' }, { id: 5, name: '2018', age: 'None' }, { id: 3, name: '2018/2019', age: 'None' }, ]; years.sort((c1, c2) => { var n1 = c1.name; var n2 = c2.name; if(n1 > n2){return -1; }else if(n2 > n1){ return 1; }else{return 0;} }); console.log(years);

Answer 3

Try this:

years.sort((c1, c2) => { if (c1.name > c2.name) return -1; if (c1.name < c2.name) return 1; return 0; }); 

Answer 4

You could use lodash _.sortBy

var years = [{id: 5, name: "2018", age: "None"}, {id: 3, name: "2018/2017", age: "None"}, {id: 1, name: "2017", age: "None"}, {id: 3, name: "2016", age: "None"}, {id: 2, name: "2015", age: "None"}] _.sortBy(years, ['name']); 

Output would be