Shell script to run Python program with command line arguments

Name: Shell script to run Python program with command line arguments - Stack Overflow
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Question

I have some files in a directory which are input files for my python script:

<1.in> <1.in.xml> <2.in> <2.in.xml> <3.in> <3.in.xml> ... .. .

I have the following till now:

for i in $(ls dir/*.in) do new = ${i%%.in} test.py -i $new.in.xml -o out_$new -x $new.in -c 56 done

When I run this, it does not create an output file (which is defined with -o option). The error is :

IOError: [Errno 2] No such file or directory

Any suggestions?

have you manually tried something like test.py -i 1.in.xml -o out_1 -x 1.in -c 56 ? would help you narrow down the problem — jon_darkstar, CommentedMar 16, 2011 at 16:14
Yes I did it manually... It runs fine when I run the python code with a single input file!!! — user638501, CommentedMar 16, 2011 at 16:29
then id have to guess new doesnt have the value you expect. can you try to echo out new right after you assign to it in each iteration? — jon_darkstar, CommentedMar 16, 2011 at 16:31
tried that also.... It gives me the value that I want it to take !!! — user638501, CommentedMar 16, 2011 at 16:43

freegnu · Accepted Answer · 2011-03-16 16:18:37Z

Make sure you are opening the file for output as open(file_name, 'w') or else the file will not be created.

I am opening the file as you suggested!
– user638501
CommentedMar 16, 2011 at 16:26 — user638501, CommentedMar 16, 2011 at 16:26

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