Select checkbox using Selenium with Python3.x and Selenium

Question

I'm trying to check the checkbox on a page: https://www.pkobp.pl/poi/?clients=1,2,3.

<li class="poi-filter-top__el"> <div class="poi-icon poi-icon--facility"></div> <input type="checkbox" id="poi-legend-facility" class="js-poi-legend" name="type" value="facility"> <label for="poi-legend-facility" class="poi-legend input-checkbox poi-filter-top__label">Oddział</label> <a href="#facility" class="js-poi-action poi-filter-top__link" data-action="facility">Wybierz rodzaj</a> </li> 

I try to do this with:

checkboxes = driver.find_elements_by_id("poi-legend-facility") for checkbox in checkboxes: if not checkbox.is_selected(): checkbox.click() 

But it doesn't work. Can you help me?

Answer 1

You have only one checkbox with such ID (poi-legend-facility).

You can do like this:

checkbox = driver.find_element_by_id("poi-legend-facility") if not checkbox.is_selected(): checkbox.click() 

Or in your case try this code:

checkboxes = driver.find_elements_by_id("poi-legend-facility") checkboxes[0].click() 

PS: Using ID for finding element faster than finding by XPath.

Answer 2

This is the the only way I could find to check all the boxes in that page and break out of loop. Give this a shot as well.

from selenium import webdriver import time driver = webdriver.Chrome() driver.get('https://www.pkobp.pl/poi/?clients=1,2,3') for tickbox in driver.find_elements_by_css_selector(".input-checkbox"): try: tickbox.click() time.sleep(7) except: break driver.quit() 

Answer 3

Try this xpath

checkElements= driver.find_element_by_xpath("//input[@type='checkbox' and @value='facility']") checkElements.click() 

I don't know python so might be syntax error but path is correct