How to open file using its default program in python

Question

How do I open a file from python? Not using the open() function and read or write, I mean simulate a user double clicking on the file. So if I open file1.jpg I want it to open using the default image program.

Thanks

Answer 1

in linux you can use xdg-open like bellow:

from subprocess import call call(['xdg-open','filename']) 

Answer 2

On windows, you get this behavior if you execute through the win32 shell. An easy way to do that is with the subprocess module:

import subprocess as subp subp.call('file1.jpg', shell=True)