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2024 YR4 is going to pass earth 20.6 Lunar distance away in 2028, then pass less than 1 lunar distance from earth in 2032. How can we slow it down with a mission in 2028 so that when it comes by in 2032 we could capture it in our orbit?

The 'why' is because of the resources from the asteroid, they could be used to build a radiation proof, micro-meteor safe space station.

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    $\begingroup$If we slow it down a substantial amount in 2028, say several m/s , it will pass much further away in 2032.$\endgroup$CommentedFeb 25 at 11:37
  • $\begingroup$This is a good point, but if we alter the orbit in a planned and careful manner, we might just intersect with the earth in 2033 instead. Couldn't we use the moon as a redirect and deceleration source to get it into orbit of earth?$\endgroup$
    – SpencerWF
    CommentedFeb 25 at 11:40
  • $\begingroup$@SpencerWF, any slowdown will make it arrive earlier, not later. Orbital mechanics is counterintuitive like that.$\endgroup$
    – Mark
    CommentedFeb 26 at 0:24

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According to its Wikipedia article,

The mass and density of 2024 YR4 have not been measured, but the mass can be loosely estimated with an assumed density and assumed diameter. Assuming a density of $2.6\,\mathrm g\,\mathrm{cm}^{-3}$, which is within the density range for stony asteroids such as 243 Ida, with an assumed diameter of 55 m (180 ft), the Sentry risk table estimates a mass of $2.2\times10^8\,\mathrm{kg}$.

Current estimates have it on an apparent trajectory that’ll get it up to around 17 kilometer per second near impact.

So, it has approximately $3.74\times10^{12}\,\mathrm{kg}\,\mathrm{m}\,\mathrm{s}^{-1}$ of momentum and approximately $7.8\,\mathrm{Mt}\,\mathrm{TNT}$ worth of kinetic energy. Compare the former to the $400,000\,\mathrm{kg}\times 8,000\,\mathrm{m}\,\mathrm{s}^{-1}=3.2\times10^9\,\mathrm{kg}\,\mathrm{m}\,\mathrm{s}^{-1}$ of the ISS, and compare the latter to a fairly-large fusion bomb.

To slow it down by ten kilometers per second to get it into orbit, we’d need to put around $6\,\mathrm{Mt}\,\mathrm{TNT}$ of kinetic energy into it (assuming it passes tangent to the low-Earth-orbit that we want it in and can do this in an impulsive maneuver), and we do not have the capacity to efficiently transfer that much energy to it without vaporizing it.

As awesome as an asteroid-ship is, we’d be riding it, not capturing it.

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    $\begingroup$All things considered, that’d probably be easier than capturing the asteroid, in terms of kinetic energy requirements. There will always be people willing to do crazy stuff for science.$\endgroup$CommentedFeb 25 at 14:11
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    $\begingroup$Using today's data, the speed of 2024 YR4 at its close approach / impact on 2032-Dec-22 08:30 TDB is ~13.31 km/s, relative to the geocentre. (And the impact probability is down to 2.7e-5).$\endgroup$
    – PM 2Ring
    CommentedFeb 25 at 14:58
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    $\begingroup$Noted, I’ll update the data in a second. Still the same result, though, there’s far too much kinetic energy for us to do anything about.$\endgroup$CommentedFeb 25 at 15:06
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    $\begingroup$@Richard Theoretically possible, but you would need a lot of them. I don't know exactly how weak they would need to be (it also depends on how much asteroid you need to survive the trip) but I'd envision something like an hourly hail of bomblets over the course of a year - thousands of individual impacts in the sub-kiloton range. Landing a thruster on it or using a gravity tractor is probably more practical and efficient at that point, and certainly less damaging to the prize.$\endgroup$
    – Cadence
    CommentedFeb 26 at 9:30
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    $\begingroup$Here are Horizons plots showing that 2024 YR4 loses angular momentum (relative to the Sun) in the 2028 encounter i.sstatic.net/53tv6iOH.png and the 2032 encounters with the Earth & Moon i.sstatic.net/FyeTRIaV.png$\endgroup$
    – PM 2Ring
    CommentedFeb 26 at 11:38

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