std::is_assignable, std::is_trivially_assignable, std::is_nothrow_assignable
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Definido no cabeçalho <type_traits> | ||
template<class T, class U > struct is_assignable; | (1) | (desde C++11) |
template<class T, class U > struct is_trivially_assignable; | (2) | (desde C++11) |
template<class T, class U > struct is_nothrow_assignable; | (3) | (desde C++11) |
Se o std::declval<T>()=std::declval<U>() expressão é bem-formado em contexto não avaliada, fornece o membro constante
2) value
true igual. Para qualquer outro tipo, é value
false.Original:
If the expression std::declval<T>()=std::declval<U>() is well-formed in unevaluated context, provides the member constant
value
equal true. For any other type, value
is false.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
mesmo que 1), mas a avaliação da expressão de atribuição não irá chamar qualquer operação que não é trivial.
3) Original:
same as 1), but evaluation of the assignment expression will not call any operation that is not trivial.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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mesmo que 1), mas a avaliação da expressão de atribuição não irá chamar qualquer operação que não está noexcept.
Original:
same as 1), but the evaluation of the assignment expression will not call any operation that is not noexcept.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Índice |
Herdado de std::integral_constant
Member constants
value [estática] | true se T is assignable from U , false contrário Original: true if T is assignable from U , false otherwise The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (membro estático público constante) |
Member functions
operator bool | converte o objeto em bool, retorna value Original: converts the object to bool, returns value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função pública membro) |
Member types
Tipo Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | Definition |
value_type | bool |
type | std::integral_constant<bool, value> |
[editar]Exemplo
#include <iostream>#include <string>#include <type_traits>struct Ex1 {int n;};int main(){std::cout<<std::boolalpha<<"int is assignable from double? "<< std::is_assignable<int, double>::value<<'\n'<<"int& is nothrow assignable from double? "<< std::is_nothrow_assignable<int&, double>::value<<'\n'<<"string is assignable from double? "<< std::is_assignable<std::string, double>::value<<'\n'<<"Ex1& is trivially assignable from const Ex1&? "<< std::is_trivially_assignable<Ex1&, const Ex1&>::value<<'\n';}
Saída:
int is assignable from double? false int& is nothrow assignable from double? true string is assignable from double? true Ex1& is trivially assignable from const Ex1&? true
[editar]Veja também
(C++11) (C++11) (C++11) | verifica se um tipo tem um operador de atribuição de cópia Original: checks if a type has a copy assignment operator The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de classe) |
(C++11) (C++11) (C++11) | verifica se um tipo tem um operador de atribuição movimento Original: checks if a type has a move assignment operator The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de classe) |