Espaços nominais
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std::is_assignable, std::is_trivially_assignable, std::is_nothrow_assignable

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Biblioteca de utilitários
Digite apoio (basic types, RTTI, type traits)
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Data e hora
Objetos de função
(C++11)
Os operadores relacionais
Original:
Relational operators
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rel_ops::operator!=
rel_ops::operator>
rel_ops::operator<=
rel_ops::operator>=
Pares e tuplas
Original:
Pairs and tuples
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(C++11)
Troque, avançar e avançar
Original:
Swap, forward and move
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(C++11)
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Apoio a tipos
Tipos básicos
Original:
Basic types
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Tipos fundamentais
Tipos inteiros de largura fixos(C++11)
Limites numéricos
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Numeric limits
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C numérico limita interface
Informações de tipo de tempo de execução
Original:
Runtime type information
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Características de tipo
Original:
Type traits
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Principais categorias de tipo
Original:
Primary type categories
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(C++11)
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(C++11)
Propriedades de tipo
Original:
Type properties
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(C++11)
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(C++11)
Operações apoiadas
Original:
Supported operations
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is_assignableis_trivially_assignableis_nothrow_assignable
(C++11)(C++11)(C++11)
Relacionamentos e consultas de propriedade
Original:
Relationships and property queries
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(C++11)
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(C++11)
Tipo modificações
Original:
Type modifications
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Transformações tipo
Original:
Type transformations
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Digite constantes traço
Original:
Type trait constants
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Definido no cabeçalho <type_traits>
template<class T, class U >
struct is_assignable;
(1) (desde C++11)
template<class T, class U >
struct is_trivially_assignable;
(2) (desde C++11)
template<class T, class U >
struct is_nothrow_assignable;
(3) (desde C++11)
1)
Se o std::declval<T>()=std::declval<U>() expressão é bem-formado em contexto não avaliada, fornece o membro constante valuetrue igual. Para qualquer outro tipo, é valuefalse.
Original:
If the expression std::declval<T>()=std::declval<U>() is well-formed in unevaluated context, provides the member constant value equal true. For any other type, value is false.
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2)
mesmo que 1), mas a avaliação da expressão de atribuição não irá chamar qualquer operação que não é trivial.
Original:
same as 1), but evaluation of the assignment expression will not call any operation that is not trivial.
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3)
mesmo que 1), mas a avaliação da expressão de atribuição não irá chamar qualquer operação que não está noexcept.
Original:
same as 1), but the evaluation of the assignment expression will not call any operation that is not noexcept.
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Índice

Herdado de std::integral_constant

Member constants

value
[estática]
true se T is assignable from U , false contrário
Original:
true if T is assignable from U , false otherwise
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(membro estático público constante)

Member functions

operator bool
converte o objeto em bool, retorna value
Original:
converts the object to bool, returns value
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(função pública membro)

Member types

Tipo
Original:
Type
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Definition
value_typebool
typestd::integral_constant<bool, value>

[editar]Exemplo

#include <iostream>#include <string>#include <type_traits>struct Ex1 {int n;};int main(){std::cout<<std::boolalpha<<"int is assignable from double? "<< std::is_assignable<int, double>::value<<'\n'<<"int& is nothrow assignable from double? "<< std::is_nothrow_assignable<int&, double>::value<<'\n'<<"string is assignable from double? "<< std::is_assignable<std::string, double>::value<<'\n'<<"Ex1& is trivially assignable from const Ex1&? "<< std::is_trivially_assignable<Ex1&, const Ex1&>::value<<'\n';}

Saída:

int is assignable from double? false int& is nothrow assignable from double? true string is assignable from double? true Ex1& is trivially assignable from const Ex1&? true

[editar]Veja também

verifica se um tipo tem um operador de atribuição de cópia
Original:
checks if a type has a copy assignment operator
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(modelo de classe)[edit]
verifica se um tipo tem um operador de atribuição movimento
Original:
checks if a type has a move assignment operator
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(modelo de classe)[edit]
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