std::filesystem::path::root_directory
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< cpp | filesystem | path
path root_directory()const; | (since C++17) | |
Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returns path().
Contents |
[edit]Parameters
(none)
[edit]Return value
The root directory of the path.
[edit]Exceptions
May throw implementation-defined exceptions.
[edit]Example
Run this code
#include <filesystem>#include <iostream>namespace fs = std::filesystem; int main(){ fs::path p = fs::current_path(); std::cout<<"The current path "<< p <<" decomposes into:\n"<<"root name "<< p.root_name()<<'\n'<<"root directory "<< p.root_directory()<<'\n'<<"relative path "<< p.relative_path()<<'\n';}
Possible output:
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into: root name "C:" root directory "\" relative path "Users\abcdef\Local Settings\temp"
[edit]See also
returns the root-name of the path, if present (public member function) | |
returns the root path of the path, if present (public member function) |